Alkali metals : sodium , potassium
alkaline earth : magnesium , calcium
the rest are transition elements... i don't know about "inner transition"
Answer:
v = 1.08 m/s
Explanation:
What is the linear speed of the 0.0500-kg sphere as its passes through its lowest point?
The decrease in PE is
d = 80.0cm * 1 / 1000m = 0.80m
h = 0.80 m /2 = 0.40 m
ΔPE = m*g*h
ΔPE = (0.0500 - 0.0200)kg * 9.8m/s² * 0.400 m
ΔPE = 0.1176 J
The moment of inertia of the assembly is
I = 1/12*m*L² + (m1 + m2)*(L/2)²
I = 1/12*0.390kg*(0.800m)² + 0.0700kg*(0.400m)²
I = 0.032 kg·m²
KE = ½Iω²
0.1176 J = ½ * 0.032kg·m² * ω²
ω = 2.71 rad/s
v = ωr = 2.71 rad/s * 0.400m
The linear velocity
v = 1.08 m/s
This problem can be solved by using oxidation states. The oxidation state is based on the electrons an atom loses or gain, or appears to use when forming compounds.To find the formula for Copper (I) Sulfide, we have to first consider the individual ions that come together to form it. Copper (I) is an ion of copper that has a charge of +1, i.e
. Sulfur is an element in group 6 of the periodic table. The sulfur ion has a charge of -2, i.e
. To form Copper (I) Sulfide, which is electrically neutral, we need 2 Copper (I) ions and 1 sulfur ion.
.
The reaction is represented by the equation below
.
The correct answer is (C)
Explanation:
(a) From E=
r
2
k
e
Q
Q=
k
e
Er
2
=
(8.99×10
9
N⋅m
2
/C
2
)
(8.90×10
2
N/C)(0.750m)
2
=5.57×10
−8
C
But Q is negative since
E
→
points inward, so
Q=−5.57×10
−8
C=−55.7nC
(b) The negatve charge has a spherically symmetric charge distribution, concentric with the spherical shell
laborious ... enclosed may help ... cos -angle = cos +plus angle ... sin - anfle = - sine angle
cos is even function, sine is odd ... draw rhe graohs