Answer:
d = 6.32 m
Explanation:
Given that,
The mass of a puck, m = 2 kg
It is pushed straight north with a constant force of 5N for 1.50 s and then let go.
We need to find the distance covered by the puck when move from rest in 2.25 s.
We know that,
F = ma
Let d is the distance moved in 2.25 s. Using second equation of motion,
So, it will move 6.32 m from rest in 2.25 seconds.
Answer:
V=34.2 m/s
Explanation:
Given that
Height , h= 54 m
Horizontal distance , x = 35 m
Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.
In vertical direction :
We know that
Now by putting the values in the above equation we got
Assume
Thus
We also know that
In horizontal direction :
Thus the resultant velocity
V=34.2 m/s
Therefore the velocity will be 34.2 m/s.