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Andreyy89
3 years ago
9

Calculate the molarity of a solution of HNO3 that contains 12.6 grams HNO3 in

Chemistry
1 answer:
just olya [345]3 years ago
6 0

Answer:

The answer os 0.2 m

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A lead apron is a ________________ instrument classification of disease transmission. Fill in the blank
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A lead apron is a <u>non-critical </u> instrument.

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7 0
2 years ago
Determine which is greater
Shkiper50 [21]
B. 1500m + 180m = 1680m and is the greatest

4 0
3 years ago
Multiple Choice Question
valina [46]

Answer:

Explanation:

i would say not d im not fully sure but id say c

6 0
3 years ago
Step 1: Translate the starting chemicals into formulas:Iron metal, in the presence of oxygen,-----&gt;Step 2: Predict the produc
Natalija [7]

Answer:

Explanation:

Here, we want to write the chemical reaction

step 1:

we start by writing the reaction between iron and oxygen

We have this as:

\text{ Fe + O}_2

step 2:

Now, we want to predict the product as follows:

\text{ Fe + O}_2\text{ }\rightarrow Fe_2O_3

step 3:

We proceed to balance the chemical reaction as follows by ensuring that the number of elements moles on the reactant side is equal to the number of moles of the elements on the products side as follows:

\text{ 4Fe + 3O}_2\text{ }\rightarrow2Fe_2O_3

3 0
1 year ago
You conduct an experiment that requires the creation of an ammonia solution. You do this by reacting 50.0 L of nitrogen gas with
ozzi

Answer : The molarity of the resulting ammonia solution is, 0.89 M

Explanation :

The balanced chemical reaction is:

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

First we have to calculate the moles of nitrogen gas.

As we know that at STP, 1 mole of gas occupies 22.4 L volume of gas.

As, 22.4 L volume of nitrogen gas present in 1 moles of nitrogen gas

So, 50.0 L volume of nitrogen gas present in \frac{50.0}{22.4}=2.23 moles of nitrogen gas

Thus, the moles of nitrogen gas is 2.23 moles.

Now we have to calculate the moles of ammonia gas.

From the reaction, we conclude that

As, 1 mole of N_2 react to give 2 mole of NH_3

So, 2.23 moles of N_2 react to give 2.23\times 2=4.46 moles of NH_3

Now we have to calculate the molarity of the resulting ammonia solution.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of ammonia}}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{4.46mole}{5.0L}

\text{Molarity}=0.89M

Therefore, the molarity of the resulting ammonia solution is, 0.89 M

7 0
3 years ago
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