12.5 mL of NaOH solution
Explanation:
We have the following chemical reaction in which sodium hydroxide (NaOH) react with acetic acid (CH₃-COOH) to form sodium acetate (CH₃-COONa) and water (H₂O):
NaOH + CH₃-COOH → CH₃-COONa + H₂O
molar concentration = number of moles / volume
number of moles = molar concentration × volume
number of moles of CH₃-COOH = 0.2 × 12.5 = 2.5 mmoles
*typically a vinegar solution have a concentration of acetic acid of 12.5 mol/L.
Taking in account the chemical reaction, we devise the following reasoning:
if 1 mmole of NaOH reacts with 1 mmole of CH₃-COOH
then X = 2.5 mmoles of NaOH reacts with 2.5 mmoles of CH₃-COOH
volume = number of moles / molar concentration
volume of NaOH solution = 2.5 / 0.2 = 12.5 mL
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molar concentration
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Answer: HF-dipole- dipole interaction
CH3OH- dipole-dipole interaction
CaCl2- ion-ion interaction
Explanation:
Both CH3OH and HF possess permanent dipoles which interact with water leading to the dissolution of the above named substances. Remember that water also possesses a permanent dipole. Which can interact with the dipoles on other polar molecules. CaCl2 is purely ionic and interacts with water via ion-dipole mechanism.
First one is balanced because all of the elements in reactant and product have equal number of atoms.
second one is not balanced therefore you need to add coefficient to balance it. so its CaCl2 + 2NaHCO3 = CO2 + CaCO3 + H2O + 2NaCl
both of them seem double replacement reaction
Hope it helps!
~ Rabin
ANSWER:
Potential energy due to the position of an object above Earth's surface is called gravitational potential energy.
EXPLANATION:
Gravitational energy is the potential energy compared with gravitational force, as work is needed to further things against Earth’s gravity. The potential energy due to high positions is called gravitational potential energy, and is evidenced by water in an elevated storage or kept behind a dam. If an article falls from one point to different point inside a gravitational field, the force of gravitation will do actual work on the object, and the gravitational potential energy will decrease by the same amount.