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OLEGan [10]
2 years ago
6

Please help on both I apologize for the horrible quality

Chemistry
1 answer:
NemiM [27]2 years ago
4 0

Answer:

Explanation:

1)

H₂SO₄:

Element (symbol)     No of atoms in         No of compounds        Total atoms

                                    1 molecule                   coefficient

H                                              2                            1                                 2

S                                               1                                                                1

O                                              4                                                               4

2)

2H₃PO₄:

Element (symbol)     No of atoms in         No of compounds        Total atoms

                                    1 molecule                   coefficient

H                                              3                            2                                 6

P                                               1                                                                2

O                                              4                                                                8

There are two mole of H₃PO₄. One mole contain 3 hydrogen atom, 1 phosphorus atom and 4 oxygen atoms. Thus in two mole of compound 6 hydrogen atoms, 2 phosphorus atom and 8 oxygen atoms are present.

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0.352 g sample of a diprotic acid is dissolved in water and titrated with 0.150 M NaOH.0.150 M NaOH. What is the molar mass of t
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<h3>Answer:</h3>

128.94 g/mol

<h3>Explanation:</h3>

Given;

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<h3>Step 1: Write the balanced equation fro the reaction;</h3>

The balanced equation for the reaction between the diprotic acid and NaOH will be;

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Given the molarity and volume of NaOH we can calculate the number of moles;

Moles of NaOH = Molarity × Volume

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<h3>Step 3: Use the mole ratio to determine moles of the acid </h3>

From the equation;

1 mole of the acid reacts with 2 moles of NaOH

Therefore; H₂x : NaOH = 1 : 2

Moles of H₂x = 0.00546 moles ÷ 2

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From our calculations;

0.00273 moles = 0.352 g of the acid;

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= 0.352 g ÷ 0.00273 moles

= 128.94 g/mol

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