The molecular equation :
MgI₂(aq) + Pb(NO₃)₂(aq) → Mg(NO₃)₂(aq) + PbI₂(s)
The net ionic equations
Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)
<h3>Further explanation</h3>
Given
Word equation
Required
The molecular equations and the net ionic equations
Solution
The chemical equation can be expressed in terms of:
- word equation
- skeleton equation
- balanced equation
The equation of a chemical reaction can be expressed in the equation of the ions
When a spectator ions are removed, the ionic equation is called the net ionic equation
A molecular equation is a chemical equation that has been balanced and is written in molecular (not ionic) form
The molecular equation :
MgI₂(aq) + Pb(NO₃)₂(aq) → Mg(NO₃)₂(aq) + PbI₂(s)
the ionic equation :
Mg²⁺ +2I⁻ + Pb²⁺ + 2NO₃⁻ → Mg²⁺ + 2NO₃⁻ + PbI₂
the net ionic equations
Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s)
Answer:
Oxygen Doesn't change
However, Li is oxidized (0 to +1), Na is reduced (+1 to 0)
Explanation:
On reactant side, Oxygen has -2 oxidation charge because we know common oxidation states such as oxygen -2, hydrogen +1 etc.
So NaOH, O is -2, H is +1, so Na has to be +1 to equal total charge of compound
In product side, LiOH, again O has to be -2, H is +1, so Li +1 as well..
We see that oxygen oxidation state doesn't change. However, for Li it becomes oxidized going from 0 to +1 whereas, Na is reduced going from +1 to 0.
Even though there is no followings, I will try to include in this answer all the possible answers. I am sure about two elements that bound to hemoglobin when hemoglobin is in the R-state :Fe+2 and O2. As you should know, <span> R-state of hemoglobin is a relaxed form that is also called</span> <span>oxyhemoglobin, so the O2 definitely must be mentioned in there.</span>
Answer: CH₃CN and H₂O.
Explanation:
1) The spieces present in a solution may be either the molecules, in case of covalent compounds, or ions, in case of ionic compounds that dissociate (ionize).
2) Both, CH₃CN and H₂O are covalent (polar covalent) substances, so they do not ionize and the spieces in the solution are the molecules per se.
3) In solution, the molecules of H₂O will solvate the molecules of CH₃CN, meaning that H₂O molecules are able to separate the molecules of CH₃N from each other, and so every molecule of CH₃CN will end surrounded by many molecules of H₂O.
This happens because the interaction between the polar molecules of the two different compounds is strong enough to overcome the intermolecular forces between the molecules of the same compound.
