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Liula [17]
3 years ago
15

Mg(OH)2+HCl=MgCl2+H2O

Chemistry
1 answer:
attashe74 [19]3 years ago
5 0
Left side:
Mg= 1
O= 2
H= 4
Cl= 2

Right side:
Mg= 1
O= 2
H= 4
Cl= 2
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Calculate the acceleration of a car if its speed increases from 4.0 m/s to 16 m/s in 3.7 s.
ioda

Answer:

3.24m/s^2

Explanation:

The following data were obtained from the question:

U = 4m/s

V = 16m/s

t = 3.7secs

Acceleration is change in velocity with time i.e

a = (V — U) / t

a = (16 — 4) / 3.7

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Complete the lewis structures of the atoms and ions by adding electrons, as needed.
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he standard enthalpies of formation for S (g), F (g), SF4 (g), and SF6 (g) are +278.8, +79.0, -775, and -1209 kJ per mole, respe
JulsSmile [24]

Answer:

+60.54 kJ/mol

Explanation:

The enthalpy of formation of a compound is the sum of the enthalpies of the formation of its constituents and the bond of them. To form a compound, energy must be lost, so, they're negative.

For SF4, the enthalpy is formed by the energy of one S, two F, and 4 S-F bond (Hb):

H = - (278.8 + 4*79.0 + 4*Hb)

-775 = -(594.8 + 4Hb)

594.8 + 4Hb = 775

4Hb = 180.2

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For SF6, the enthalpy is formed by the energy of one S, six F, and 6 S--F bonds (Hb):

H = -(278.8 + 6*79.0 + 6*Hb)

-1209 = -(752.8 + 6Hb)

752.8 + 6Hb = 1209

6Hb = 456.2

Hb = +76.03 kJ/mol

Thus, the energy of S--F bond must be the average of these two:

(45.05 + 76.03)/2 = +60.54 kJ/mol

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As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy.
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