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leva [86]
2 years ago
5

This activity asks you to sort items according to the most appropriate method for viewing. For each of the following items, indi

cate which viewing method is most appropriate–the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy–by dragging it into the correct bin.
Physics
1 answer:
postnew [5]2 years ago
6 0

Based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

<h3>What kind of items are the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy used to view?</h3>

In viewing objects, the size and nature of the object determines which instrument it is viewed with.

The unaided eye is used to view large size objects such as insects and plants

The light microscope is used to view smaller objects such as red blood cells.

Scanning electron microscopy is used view ultramicroscopic living and non-living sample such as the tissues, cells, etc.

Transmission electron microscopy is used to view even smaller objects. It has a higher resolution than scanning electron microscopy.

Therefore, based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

Learn more about microscopy at: brainly.com/question/15744335

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A spring stretches by 0.0208 m when a 3.39-kg object is suspended from its end. How much mass should be attached to this spring
sashaice [31]

Answer:

COMPLETE QUESTION

A spring stretches by 0.018 m when a 2.8-kg object is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 3.0 Hz?

Explanation:

Given that,

Extension of spring

x = 0.0208m

Mass attached m = 3.39kg

Additional mass to have a frequency f

Let the additional mass be m

Using Hooke's law

F= kx

Where F = W = mg = 3.39 ×9.81

F = 33.26N

Then,

F = kx

k = F/x

k = 33.26/0.0208

k = 1598.84 N/m

The frequency is given as

f = ½π√k/m

Make m subject of formula

f² = ¼π² •(k/m

4π²f² = k/m

Then, m4π²f² = k

So, m = k/(4π²f²)

So, this is the general formula,

Then let use the frequency above

f = 3Hz

m = 1598.84/(4×π²×3²)

m = 4.5 kg

4 0
3 years ago
The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity betwee
aniked [119]

Answer: 15m/s

Explanation: <u>Average</u> <u>Velocity</u> is vector describing the total displacement of an object and the time taken to change its position. It is represented as:

v=\frac{\Delta x}{\Delta t}

At t₁ = 1.0s, displacement x₁ is:

x(1)=25+3(1)^{2}

x(1) = 28

At t₂ = 4.0s:

x(4)=25+3(4)^{2}

x(4) = 73

Then, average speed is

v=\frac{73-28}{4-1}

v = 15

The average velocity of a car between t₁ = 1s and t₂ = 4s is 15m/s

5 0
2 years ago
A hungry hawk was preying on a lizard who was running northwards to get away from the low-flying hawk. If the lizard can run 8m
Anastaziya [24]

Answer:

2m/s²

Explanation:

velocity = displacement (distance in a specified direction /time

8 0
3 years ago
Acceleration increases over time once a force is applied to the object. Determine the acceleration at 3.5 sec? A) 3 m/s2 B) 6 m/
Novay_Z [31]

Answer: Acceleration does not increase over time once a force is applied to the object. It depends on the force and the object's mass. If those don't change, then the acceleration is constant.

Explanation:. F = M • a

We don't know either of those numbers, so we can't answer the question.

4 0
3 years ago
Read 2 more answers
I need help with these questions.
strojnjashka [21]

I'll go ahead and answer the ones here without an answer. For reference, the half-life formula is <em>final amount = original amount(1/2)^(time/half-life)</em>

<em />

4) 12.5g

x = 100(1/2)^(63/21)

5) 50g

3.125 = x(1/2)^(0.1/0.025)

6) 500g

x = 4000(1/2)^(525/175)

7) 0.24g

0.06 = x(1/2)^(11430/5730)

8) 125g

x = 1000(1/2)^(17100/5700)

Hope this helps! :)

4 0
3 years ago
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