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leva [86]
3 years ago
5

This activity asks you to sort items according to the most appropriate method for viewing. For each of the following items, indi

cate which viewing method is most appropriate–the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy–by dragging it into the correct bin.
Physics
1 answer:
postnew [5]3 years ago
6 0

Based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

<h3>What kind of items are the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy used to view?</h3>

In viewing objects, the size and nature of the object determines which instrument it is viewed with.

The unaided eye is used to view large size objects such as insects and plants

The light microscope is used to view smaller objects such as red blood cells.

Scanning electron microscopy is used view ultramicroscopic living and non-living sample such as the tissues, cells, etc.

Transmission electron microscopy is used to view even smaller objects. It has a higher resolution than scanning electron microscopy.

Therefore, based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

Learn more about microscopy at: brainly.com/question/15744335

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Are the units of the formula ma = mv2/2 dimensionally consistent? Select the single best answer.
Vesnalui [34]

To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency

ma = \text{Mass}\times \text{Acceleration}

ma = kg \cdot \frac{m}{s^2}

At the same time we have that

\frac{1}{2}mv^2 = \text{Mass}\times \text{Velocity}^2

\frac{1}{2}mv^2 = kg ( \frac{m}{s})^2

\frac{1}{2}mv^2 = kg \cdot \frac{m^2}{s^2}

Therefore there is not have same units and both are not consistent and the correct answer is B.

5 0
4 years ago
Topics related to physics​
Bezzdna [24]

Answer:

There are many topics related to physics such as :

Kinematics

Dynamics

Light

Sound

7 0
2 years ago
The average daily demand for component B is 750 units. The average time for waiting during the production process and materials
Greeley [361]

Answer:

4 containers

Explanation:

Given

Average daily demand, d= 750 units

Average time for waiting during production and materials handling, w = 0.15 days

Processing time per container, t = 0.1 days

Container capacity, c = 50 units

Policy variable, α = 5% = 0.05

Number of containers required for component​ B is calculated as follows;

Total Production/Container Capacity.

Total Production = d(w + t)(1 + α)

Total Production = 750 * (0.15 + 0.1) * (1 + 0.05)

Total Production = 196.875

Number of containers = 196.875/50

Number of containers = 3.9375

Number of containers = 4 --- approximated

7 0
3 years ago
Read 2 more answers
Figure P2.23 is a somewhat simplified velocity graph for Olympic sprinter Carl Lewis starting a 100 m dash. Estimate his acceler
ehidna [41]

A) Acceleration in part A: 6.1 m/s^2

B) Acceleration in part B: 2.7 m/s^2

C) Acceleration in part C: 1.5 m/s^2

Explanation:

A)

The picture of the problem is missing: find it in attachment.

The acceleration of a body is equal to the rate of change of its velocity:

a=\frac{v-u}{\Delta t}

where

v is the final velocity

u is the initial velocity

\Delta t is the time it takes for the velocity to change from u to v

In part A of the race, we have:

u = 0

v = 5.5 m/s (estimate)

\Delta t = 0.9 - 0 = 0.9 s

So the acceleration is

a=\frac{5.5-0}{0.9}=6.1 m/s^2

B)

In part B of the race, we have:

u = 5.5 m/s is the initial velocity (estimate)

v = 9.5 m/s is the final velocity (estimate)

\Delta t = 2.4 - 0.9 = 1.5 s is the time interval between the two points considered

Therefore, using the equation for the acceleration, we can find the acceleration in part B:

a=\frac{9.5-5.5}{1.5}=2.7 m/s^2

C)

In part C of the race, we have:

u = 9.5 m/s is the initial velocity (estimate)

v = 11 m/s is the final velocity (estimate)

\Delta t = 3.4 - 2.4 = 1 s is the time interval between the two points considered

And therefore, the acceleration in part C of the race is:

a=\frac{11-9.5}{1}=1.5 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

3 0
3 years ago
Draw a diagram showing 2 forces acting on an object in opposite directions with a total net force of 3N to the left.
andriy [413]

Answer:

hope it helps u ........

6 0
2 years ago
Read 2 more answers
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