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leva [86]
3 years ago
5

This activity asks you to sort items according to the most appropriate method for viewing. For each of the following items, indi

cate which viewing method is most appropriate–the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy–by dragging it into the correct bin.
Physics
1 answer:
postnew [5]3 years ago
6 0

Based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

<h3>What kind of items are the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy used to view?</h3>

In viewing objects, the size and nature of the object determines which instrument it is viewed with.

The unaided eye is used to view large size objects such as insects and plants

The light microscope is used to view smaller objects such as red blood cells.

Scanning electron microscopy is used view ultramicroscopic living and non-living sample such as the tissues, cells, etc.

Transmission electron microscopy is used to view even smaller objects. It has a higher resolution than scanning electron microscopy.

Therefore, based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

Learn more about microscopy at: brainly.com/question/15744335

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The four living things seen here, dog, flower, algae, and bacteria, are all made of cells. A - C are multicellular, but D is uni
djverab [1.8K]
B) They are all made up of at least one cell
6 0
3 years ago
Read 2 more answers
A ball is thrown upward from the top of a building at an angle of 30.0° to the horizontal and with
Ray Of Light [21]

Answer:

See below

Explanation:

Vertical position = 45 +  20 sin (30) t  - 4.9 t^2

 when it hits ground this = 0

               0 = -4.9t^2 + 20 sin (30 ) t + 45

                0 = -4.9t^2 + 10 t +45 = 0     solve for t =4.22 sec

  max height is at  t= - b/2a = 10/9.8 =1.02

     use this value of 't' in the equation to calculate max height = 50.1 m

      it has  4.22 - 1.02 to free fall = 3.2 seconds free fall

           v = at = 9.81 * 3.2 = 31.39 m/s VERTICAL

      it will <u>also</u> still have horizontal velocity =  20 cos 30 = 17.32 m/s

        total velocity will be sqrt ( 31.39^2 + 17.32^2) = 35.85 m/s

Horizontal range = 20 cos 30  * t  =  20 *  cos 30  * 4.22 = 73.1 m

8 0
2 years ago
A petrol engine that transforms 1000J of chemical potential energy into 300J of kinetic energy, and 700J into wasted heat and so
sergey [27]

Answer:

Efficiency = 30% = 0.3

Explanation:

The general formula for efficiency of a device is given as:

Efficiency = (Desired Output/ Input) * 100%

Here, in our case, we have a petrol engine as a device. So, we analyze it for the efficiency calculations. Here, we have:

Chemical Potential Energy = 1000 J

Kinetic Energy = 300 J

Heat and Sound Energy = 700 J

Now, we know that the desired output of a car or the purpose of a car is to provide Kinetic energy, while all other forms of energy such as heat and sound energies are produced as waste. And the chemical energy is provided to car as input, in form of fuel. Therefore,

Input = Chemical Potential Energy = 1000 J

Desired Output = Kinetic Energy = 300 J

Therefore,

Efficiency = (300 J/1000 J) * 100%

<u>Efficiency = 30% = 0.3</u>

4 0
3 years ago
A circus tightrope walker weighing 800 N is standing in the middle of a 15 meter long cable stretched between two posts. The cab
Lorico [155]

Answer:

T = 10010 N

Explanation:

To solve this problem we must use the translational equilibrium relation, let's set a reference frame

X axis

       Fₓ-Fₓ = 0

       Fₓ = Fₓ

whereby the horizontal components of the tension in the cable cancel

Y Axis  

        F_{y} + F_{y} - W =0

        2F_{y} = W

let's use trigonometry to find the angles

        tan θ = y / x

        θ = tan⁻¹ (0.30 / 0.50 L)

        θ = tan⁻¹ (0.30 / 0.50 15)

        θ = 2.29º

the components of stress are

         F_{y} = T sin θ

we substitute

       2 T sin θ = W

       T = W / 2sin θ

        T = \frac{ 800}{ 2sin 2.29}

        T = 10010 N

4 0
3 years ago
A person, whose eye has a lens-to-retina distance of 2.0 cm, can only clearly see objects that are closer than 1.0 m away. what
shutvik [7]

To calculate the strength of the eye lens, we use the formula

\frac{P}{100} = \frac{1}{f} =\frac{1}{u} +\frac{1}{v}  ( thin lens formula)

Here, u is the object distance and v is image distance.

Given, u =1 m=100cm and v = 2 cm

Therefore,

\frac{1}{f} =\frac{1}{100} + \frac{1}{2}

\frac{1}{f} = 0.01 + 0.5= 0.51 cm

Thus, strength of the eye lens is

P= \frac{100}{f} =\frac{100}{\frac{1}{0.51} } = 51 D



5 0
3 years ago
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