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leva [86]
3 years ago
5

This activity asks you to sort items according to the most appropriate method for viewing. For each of the following items, indi

cate which viewing method is most appropriate–the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy–by dragging it into the correct bin.
Physics
1 answer:
postnew [5]3 years ago
6 0

Based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

<h3>What kind of items are the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy used to view?</h3>

In viewing objects, the size and nature of the object determines which instrument it is viewed with.

The unaided eye is used to view large size objects such as insects and plants

The light microscope is used to view smaller objects such as red blood cells.

Scanning electron microscopy is used view ultramicroscopic living and non-living sample such as the tissues, cells, etc.

Transmission electron microscopy is used to view even smaller objects. It has a higher resolution than scanning electron microscopy.

Therefore, based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

Learn more about microscopy at: brainly.com/question/15744335

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erastovalidia [21]

Answer:

A)

Explanation:

8 0
3 years ago
An above ground swimming pool of 30 ft diameter and 5 ft depth is to be filled from a garden hose (smooth interior) of length 10
STALIN [3.7K]

This question involves the concepts of dynamic pressure, volume flow rate, and flow speed.

It will take "5.1 hours" to fill the pool.

First, we will use the formula for the dynamic pressure to find out the flow speed of water:

P=\frac{1}{2}\rho v^2\\\\v=\sqrt{\frac{2P}{\rho}}

where,

v = flow speed = ?

P = Dynamic Pressure = 55 psi(\frac{6894.76\ Pa}{1\ psi}) = 379212 Pa

\rho = density of water = 1000 kg/m³

Therefore,

v=\sqrt{\frac{2(379212\ Pa)}{1000\ kg/m^3}}

v = 27.54 m/s

Now, we will use the formula for volume flow rate of water coming from the hose to find out the time taken by the pool to be filled:

\frac{V}{t} = Av\\\\t =\frac{V}{Av}

where,

t = time to fill the pool = ?

A = Area of the mouth of hose = \frac{\pi (0.015875\ m)^2}{4} = 1.98 x 10⁻⁴ m²

V = Volume of the pool = (Area of pool)(depth of pool) = A(1.524 m)

V = [\frac{\pi (9.144\ m)^2}{4}][1.524\ m] = 100.1 m³

Therefore,

t = \frac{(100.1\ m^3)}{(1.98\ x\ 10^{-4}\ m^2)(27.54\ m/s)}\\\\

<u>t = 18353.5 s = 305.9 min = 5.1 hours</u>

Learn more about dynamic pressure here:

brainly.com/question/13155610?referrer=searchResults

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