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leva [86]
2 years ago
5

This activity asks you to sort items according to the most appropriate method for viewing. For each of the following items, indi

cate which viewing method is most appropriate–the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy–by dragging it into the correct bin.
Physics
1 answer:
postnew [5]2 years ago
6 0

Based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

<h3>What kind of items are the unaided eye, light microscopy, scanning electron microscopy, or transmission electron microscopy used to view?</h3>

In viewing objects, the size and nature of the object determines which instrument it is viewed with.

The unaided eye is used to view large size objects such as insects and plants

The light microscope is used to view smaller objects such as red blood cells.

Scanning electron microscopy is used view ultramicroscopic living and non-living sample such as the tissues, cells, etc.

Transmission electron microscopy is used to view even smaller objects. It has a higher resolution than scanning electron microscopy.

Therefore, based on ability to view decreasing particle sizes, the instrument employed is: unaided eye, light microscopy, scanning electron microscopy and transmission electron microscopy.

Learn more about microscopy at: brainly.com/question/15744335

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Give examples of plants that can reproduce by vegetative reproduction.​
marishachu [46]

Answer:

Some examples of vegetative propagation are farmers creating repeated crops of apples, corn, mangoes or avocados through asexual plant reproduction rather than planting seeds. Vegetative propagation can be accomplished from side-shoots, slips, stems and sections of tubers, bulbs or rhizomes.

Explanation:

5 0
3 years ago
When an object (like a ball) falls, some of its___ energy changes to ___ energy, due to the law of conservation of energy
Alinara [238K]

Answer:

potential, kinetic

Explanation:

pls give brainliest :p

8 0
2 years ago
In a Hydrogen atom an electron rotates around a stationary proton in a circular orbit with an approximate radius of r =0.053nm.
leonid [27]

Answer:

(a): F_e = 8.202\times 10^{-8}\ \rm N.

(b): F_g = 3.6125\times 10^{-47}\ \rm N.

(c): \dfrac{F_e}{F_g}=2.27\times 10^{39}.

Explanation:

Given that an electron revolves around the hydrogen atom in a circular orbit of radius r = 0.053 nm = 0.053\times 10^{-9} m.

Part (a):

According to Coulomb's law, the magnitude of the electrostatic force of interaction between two charged particles of charges q_1 and q_2 respectively is given by

F_e = \dfrac{k|q_1||q_2|}{r^2}

where,

  • k = Coulomb's constant = 9\times 10^9\ \rm Nm^2/C^2.
  • r = distance of separation between the charges.

For the given system,

The Hydrogen atom consists of a single proton, therefore, the charge on the Hydrogen atom, q_1 = +1.6\times 10^{-19}\ C.

The charge on the electron, q_2 = -1.6\times 10^{-19}\ C.

These two are separated by the distance, r = 0.053\times 10^{-9}\ m.

Thus, the magnitude of the electrostatic force of attraction between the electron and the proton is given by

F_e = \dfrac{(9\times 10^9)\times |+1.6\times 10^{-19}|\times |-1.6\times 10^{-19}|}{(0.053\times 10^{-9})^2}=8.202\times 10^{-8}\ \rm N.

Part (b):

The gravitational force of attraction between two objects of masses m_1 and m_1 respectively is given by

F_g = \dfrac{Gm_1m_2}{r^2}.

where,

  • G = Universal Gravitational constant = 6.67\times 10^{-11}\ \rm Nm^2/kg^2.
  • r = distance of separation between the masses.

For the given system,

The mass of proton, m_1 = 1.67\times 10^{-27}\ kg.

The mass of the electron, m_2 = 9.11\times 10^{-31}\ kg.

Distance between the two, r = 0.053\times 10^{-9}\ m.

Thus, the magnitude of the gravitational force of attraction between the electron and the proton is given by

F_g = \dfrac{(6.67\times 10^{-11})\times (1.67\times 10^{-27})\times (9.11\times 10^{-31})}{(0.053\times 10^{-9})^2}=3.6125\times 10^{-47}\ \rm N.

The ratio \dfrac{F_e}{F_g}:

\dfrac{F_e}{F_g}=\dfrac{8.202\times 10^{-8}}{3.6125\times 10^{-47}}=2.27\times 10^{39}.

6 0
3 years ago
Max ran 100 feet in 10 seconds.
Ivanshal [37]

Answer:

for max :

100 feet in 10 secs

for molly :

60 feet in 5 secs = 120 feet in 10 secs

so, molly ran farther in the same time interval i.e. covered 120 feet where as Max covered 100 feet

Explanation:

brainliest plz

8 0
2 years ago
Read 2 more answers
You are standing on a moving bus, facing forward, and you suddenly fall forward. You can imply form this that the bus’s
aleksley [76]
I think has stopped maybe
8 0
3 years ago
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