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shutvik [7]
3 years ago
10

Which of the following elements is in the same group as Sulfur (S)?

Chemistry
1 answer:
ikadub [295]3 years ago
4 0

Answer:

<u><em>PLEASE SHOW ME THE ELEMENTS OR I WOULD ENLIST ALL THE ELEMENTS.</em></u>

Explanation:

Group 6A (or VIA) of the periodic table are the chalcogens: the nonmetals oxygen (O), sulfur (S), and selenium (Se), the metalloid tellurium (Te), and the metal polonium (Po)

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Any molecules can have this force between them?.
RoseWind [281]

Answer:

Intermolecular bonds are found in all of them. They can come in different versions.

5 0
3 years ago
According to VSEPR theory, if there are three electron domains in the valence shell of an atom, they will be arranged in a(n) __
wolverine [178]

Answer:  B. trigonal planar

Explanation:

Valence Shell Electron Pair Repulsion Theory (VSEPR) is a model to predict the geometry of the atoms making up a molecule where atoms are arranged such that the forces of repulsion are minimum.

If a central atom is bound to three electron domains ,the number of electron pairs is 3, that means the hybridization will be sp^2 and the electronic geometry of the molecule will be trigonal planar as the electron pairs will repel each other and attain a position which is most stable.

Example: BCl_3 with 3 electron domains has trigonal planar geometry.

6 0
3 years ago
Sodium azide, NaN3, the explosive compound found in automobile air bags, decomposes according to the following equation: 2NaN3(s
shutvik [7]

Answer:

1.9 × 10² g NaN₃

1.5 g/L

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles of N₂ formed

N₂ occupies a 80.0 L bag at 1.3 atm and 27 °C (300 K). We will calculate the moles of N₂ using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.3 atm × 80.0 L / (0.0821 atm.L/mol.K) × 300 K = 4.2 mol

We can also calculate the mass of nitrogen using the molar mass (M) 28.01 g/mol.

4.2 mol × 28.01 g/mol = 1.2 × 10² g

Step 3: Calculate the mass of NaN₃ needed to form 1.2 × 10² g of N₂

The mass ratio of NaN₃ to N₂ is 130.02:84.03.

1.2 × 10² g N₂ × 130.02 g NaN₃/84.03 g N₂ = 1.9 × 10² g NaN₃

Step 4: Calculate the density of N₂

We will use the following expression.

ρ = P × M / R × T

ρ = 1.3 atm × 28.01 g/mol / (0.0821 atm.L/mol.K) × 300 K = 1.5 g/L

5 0
3 years ago
the position-time graph shows the motion of four people. label the lines on graph need on the motion description in this table.​
sertanlavr [38]
Line 1: straight horizontal line
Line 2: straight line at a slope
Line 3: exponential growth curve
Line 4: the topmost curve (the one that initially increases but then starts levels out)
3 0
3 years ago
9. Elements that are characterized by the filling of p orbitals are classified as
Bogdan [553]

Answer:

p block elements

Explanation:

6 0
3 years ago
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