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shutvik [7]
3 years ago
10

Which of the following elements is in the same group as Sulfur (S)?

Chemistry
1 answer:
ikadub [295]3 years ago
4 0

Answer:

<u><em>PLEASE SHOW ME THE ELEMENTS OR I WOULD ENLIST ALL THE ELEMENTS.</em></u>

Explanation:

Group 6A (or VIA) of the periodic table are the chalcogens: the nonmetals oxygen (O), sulfur (S), and selenium (Se), the metalloid tellurium (Te), and the metal polonium (Po)

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Suppose you are working in a chemistry lab and trying to make a solution of a substance called Sodium Chloride (which is a solid
Alenkasestr [34]

Answer:

a weighing balance, a measuring cylinder, a spatula, a beaker/flask, and a stirrer

Explanation:

The lab apparatus that would be needed to prepare a solution of sodium chloride would be <em>a weighing balance, a measuring cylinder, a spatula, a beaker/flask, and a stirrer.</em>

The weighing balance would be used to weigh out the required amount of sodium chloride. The beaker or flask would be placed on the weighing balance and its weight zeroed. The spatula would then be sued to take out the sodium chloride from its container into the beaker till the required amount is reached. The measuring cylinder would then be used to measure out the required volume of water which would be added to the salt in the beaker. The stirrer would then be used to stir the mixture in order for the salt to dissolve.

7 0
3 years ago
Another gas was used for many years to float transportation balloons.
Alja [10]
Another gas that was used to fill balloons was hydrogen. The reason why hydrogen is not used today is because it use to cause many fires when it was used to fill balloons up.

Hope I helped you! :)
6 0
3 years ago
1 point If the boy is pushing with 50N of force and the static friction resistance is 70N of force, what will happen? *​
solniwko [45]
Nothing, he shouldn’t be able to move it. Think about it like this say you try really hard to push something that is 5,000 pounds and you push as hard as you can. Well you can’t move it bc it weighs more than you can push. I’m sure their is a equation you can use to see how much you can push (body weight=force?)
6 0
3 years ago
For each of the following compounds, state whether it is ionic or covalent, and if it is ionic, write the symbols for the ions i
kupik [55]

Answer :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

All the polyatomic ions always form an ionic compound.

Polyatomic ions : It is a charged species that composed of two or more atoms and these charged species are bonded by the covalent bond.

For the given options:

Option A:  KClO_4

This compound is formed by the combination of potassium, K^+ which is a metal and ClO_4^- ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option B:  Mg(C_2H_3O_2)_2

This compound is formed by the combination of magnesium, Mg^{2+} which is a metal and C_2H_3O_2^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option C:  H_2S

Hydrogen and sulfur, both are non-metals and they will form a covalent compound.

Option D:  Ag_2S

This compound is formed by the combination of silver, Ag^{+} which is a metal and sulfur, S^{2-} which is a non-metal. Thus, it will form an ionic compound.

Option E:  N_2Cl_4

Nitrogen and chlorine, both are non-metals and they will form a covalent compound.

Option F:  Co(NO_3)_2

This compound is formed by the combination of cobalt, Co^{2+} which is a metal and NO_3^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

6 0
3 years ago
calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.
Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

Water potential = Pressure potential + solute potential

P_w=P_p+P_s

P_w=P_p+(-iCRT)

We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= P_w

P_p=0 bar (At standard temperature)

P_s=-iCRT=-\times 1\times 8.314\times 10^{-2}bar L/mol K\times 273.15 K=-3.406 bar

P_w=0 bar+(-3.406 ) bar

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

7 0
3 years ago
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