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3 years ago

I need to know the answers

Chemistry

1 answer:

suter [353]3 years ago

3 0

If you notice in the graph for antibiotic A, the number of bacteria actually INCREASES as time increases after the antibiotic was given. In the second graph, the amount of bacteria increases just a little bit (likely as the antibiotic sets in) and then decreases until no bacteria is left at all. This means that the antibiotic was the most successful because not only did the amount of bacteria decrease over time, but also all of the bacteria were eventually killed.

The last graph is shown as no antibiotic given. This is a graph showing the control group. There is always a control group in an experiment where nothing is done to the group. This is used to compare the results in the end of the experiment.

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3 years ago

At which temperature would a reaction with H -92 kJ/mol, S -0.199 kJ/(mol-K) be spontaneous? A.600k B.500k C.400k D.700k

stiv31 [10]

Given information : H = -92 KJ/mol and S = -0.199 KJ/(mol.K)

At equilibrium G = 0

We have to find the Temperature at which reaction would be spontaneous.

For spontaneous reaction : $\triangle G = negative (-)$

For non-spontaneous reaction : $\triangle G = positive (+)$

We can find the temperature using the formula for Gibbs free energy which is:

$\triangle G = \bigtriangleup H - T\bigtriangleup S$

Where, G = Gibbs free energy ,

H = Enthalpy

S = Entropy

T = Temperature

By plugging the value of G , H and S in the above formula we can find 'T'

$\triangle G = \bigtriangleup H - T\bigtriangleup S$

Since reaction should be spontaneous that means $\triangle G$ should be negative , so the above formula can be written as :

$\triangle G < \bigtriangleup H - T\bigtriangleup S$

On rearranging the above formula we get :

$0 < \bigtriangleup H - T\bigtriangleup S$

$T < \frac{\bigtriangleup H}{\bigtriangleup S}$

$T < \frac{-92\frac{KJ}{mol}}{-0.199\frac{KJ}{mol.K}}$

$T < (\frac{-92}{-0.199})\times (\frac{KJ}{mol})\times (\frac{mol.K}{KJ})$

$T < 462.3 K$

For the reaction to be spontaneous , T should be less than 462.3 K, so out of given option , C is correct which is 400 K.

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