p(x)= x-2
g(x)= 2x^3 + 3x^2 - 11x - 6
first we have to find the zero of the polynomial of x-2
p(x)= x-2 = 0
x=2
therefore,
p(x)= 2x^3 + 3x^2 - 11x - 6
p(2)= 2*2^3 + 3*2^2 - 11*2 - 6
= 2*8 + 3*4 - 11*2 - 6
= 16 + 12 - 22 - 6
= 28-28
= 0
Hope it helped u, ^_^.
Answer:
8\sqrt{2}\ units.
Step-by-step explanation:
Use the trignometric property.
sin\theta = \frac{Perpendicular}{Hypotenuse}
Perpendicular = 8
Hypotenuse = h
\theta = 45^{\circ}
sin\ 45^{\circ} = \frac{1}{\sqrt{2}}
\frac{1}{\sqrt{2}} = \frac{8}{h}
h = 8\sqrt{2}\ units
Hope I helped you! x
Answer:
Step-by-step explanation:
given that diameter of the pipe = 14 inches
radius = 7 inches
Length =2156 inches
Pipe is in the form of a cylinder
Volume of cylinder = pi r^2 h
where r = radius and h = l = 2156
We have to substitute the values of r and h.
Let us take pi as 22/7
= 22/7 (7)(7)(2156)
Cancel out 7 and multiply the remaining 22 ,7 and 2156
=332024 cubic inches
The answer I believe is c