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kumpel [21]
3 years ago
12

Why are “input” and “output” good words to use when discussing systems?

Physics
2 answers:
Ahat [919]3 years ago
4 0

Answer:

Because it gives a direct relation that can be used to obtain the efficiency E = Input/output which tell us how the system works, for example, if the efficiency is bigger than one, this means that the system amplifies the input (the output is bigger than the input) while if the efficiency is less than one, the output is smaller than the input.

Where these quantities can be forces, heat, electricity, or anything.

charle [14.2K]3 years ago
3 0

Answer:

To determine how efficient that system is.

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Answer:

400 N

Explanation:

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7 0
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Calculate the entropy change that occurs when 1.0kg of water at 20.00 C is mixed with 2.0kg of water at 80.00 C
SOVA2 [1]

Answer:

The change in entropy ΔS = 0.0011 kJ/(kg·K)

Explanation:

The given information are;

The mass of water at 20.0°C = 1.0 kg

The mass of water at 80.0°C = 2.0 kg

The heat content per kg of each of the mass of water is given as follows;

The heat content of the mass of water at 20.0°C = h₁ = 83.92 KJ/kg

The heat content of the mass of water at 80.0°C = h₂ = 334.949 KJ/kg

Therefore, the total heat of the the two bodies = 83.92 + 2*334.949 = 753.818 kJ/kg

The heat energy of the mixture =

1 × 4200 × (T - 20) = 2 × 4200 × (80 - T)

∴ T = 60°C

The heat content, of the water at 60° = 251.154 kJ/kg

Therefore, the heat content of water in the 3 kg of the mixture = 3 × 251.154 = 753.462

The change in entropy ΔS = ΔH/T = (753.818 - 753.462)/(60 + 273.15) = 0.0011 kJ/(kg·K).

8 0
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A

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An object, 5 cm high, is placed on the principal axis of a diverging lens of focal length 20 cm. The object is 30 cm from the le
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3 0
3 years ago
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