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Lisa [10]
3 years ago
8

A small disk of radius R1 is mounted coaxially with a larger disk of radius R2. The disks are securely fastened to each other an

d the combination is free to rotate on a fixed axle that is perpendicular to a horizontal frictionless table top, as shown in the overhead view below. The rotational inertia of the combination is I. A string is wrapped around the larger disk and attached to a block of mass m, on the table. Another string is wrapped around the smaller disk and is pulled with a force F as shown. The acceleration of the block is:
Physics
1 answer:
murzikaleks [220]3 years ago
3 0

Answer:

Explanation:

For moment of inertia, the mass will appear as a point mass on the rim of the larger radius.

Total moment of inertia of the system is (I + mR₂²)

torque is FR₁

α = τ/I = FR₁/(I + mR₂²)

a = R₂α = R₂(FR₁/(I + mR₂²))

a = FR₁R₂/(I + mR₂²)

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3 years ago
A) 1.2-kg ball is hanging from the end of a rope. The rope hangs at an angle 20° from the vertical when a 19 m/s horizontal wind
Marat540 [252]

Answer:

Part a)

F_v = 4.28 N

Part B)

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Part C)

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Explanation:

Part A)

As we know that ball is hanging from the top and its angle with the vertical is 20 degree

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Tcos\theta = mg

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Part B)

Here we can use energy theorem to find the distance that it will move

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(-3.5 + 2.54)L = - 0.98

L = 1.02 m

Part C)

At terminal speed condition we know that

F_v = mg

bv^2 = mg

2.5 v^2 = 3.9

v = 1.25 m/s

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