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MrMuchimi
3 years ago
13

Which is an example of a chemical change?

Chemistry
2 answers:
nordsb [41]3 years ago
7 0

Answer:

C

Explanation:

Chemical change is baking a cake;)

expeople1 [14]3 years ago
7 0
Backing a cake that the answer
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Given the following data:
bagirrra123 [75]

176.0 \; \text{kJ} \cdot \text{mol}^{-1}

As long as the equation in question can be expressed as the sum of the three equations with known enthalpy change, its \Delta H can be determined with the Hess's Law. The key is to find the appropriate coefficient for each of the given equations.

Let the three equations with \Delta H given be denoted as (1), (2), (3), and the last equation (4). Let a, b, and c be letters such that a \times (1) + b \times (2) + c \times (3) = (4). This relationship shall hold for all chemicals involved.

There are three unknowns; it would thus take at least three equations to find their values. Species present on both sides of the equation would cancel out. Thus, let coefficients on the reactant side be positive and those on the product side be negative, such that duplicates would cancel out arithmetically. For instance, 3 + (-1) = 2 shall resemble the number of \text{H}_2 left on the product side when the second equation is directly added to the third. Similarly

  • \text{NH}_4 \text{Cl} \; (s): -2 \; a = 1
  • \text{NH}_3\; (g): -2 \; b = -1
  • \text{HCl} \; (g): 2 \; c = -1

Thus

a = -1/2\\b = 1/2\\c = -1/2 and

-\frac{1}{2} \times (1) + \frac{1}{2} \times (2) - \frac{1}{2} \times (3)= (4)

Verify this conclusion against a fourth species involved- \text{N}_2 \; (g) for instance. Nitrogen isn't present in the net equation. The sum of its coefficient shall, therefore, be zero.

a + b = -1/2 + 1/2 = 0

Apply the Hess's Law based on the coefficients to find the enthalpy change of the last equation.

\Delta H _{(4)} = -\frac{1}{2} \; \Delta H _{(1)} + \frac{1}{2} \; \Delta H _{(2)} - \frac{1}{2} \; \Delta H _{(3)}\\\phantom{\Delta H _{(4)}} = -\frac{1}{2} \times (-628.9)+ \frac{1}{2} \times (-92.2) - \frac{1}{2} \times (184.7) \\\phantom{\Delta H _{(4)}} = 176.0 \; \text{kJ} \cdot \text{mol}^{-1}

3 0
3 years ago
To achieve an octet in the valence energy level, a fluorine atom will gain two electrons?
solmaris [256]
1 electron. Look at the periodic table, fluorine (F) is on the right, atomic number 9. It wants to get all the way over to the right to become more stable, which means it only needs 1 more electron (has 7 in its current state, wants 8)
4 0
4 years ago
Read 2 more answers
odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add
Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

Explanation :

First we have to calculate the moles of H_2SO_4.

\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}

Given:

Molar mass of H_2SO_4 = 98 g/mole

Mass of H_2SO_4 = 6.05\times 10^3kg=6.05\times 10^6g

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol

The moles of H_2SO_4 is, 6.17\times 10^4mol

Now we have to calculate the moles of Na_2CO_3

The balanced neutralization reaction is:

Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3

From the balanced chemical reaction we conclude that,

As, 1 mole of H_2SO_4 neutralizes 1 mole of Na_2CO_3

So, 6.17\times 10^4mol of H_2SO_4 neutralizes

Now we have to calculate the mass of Na_2CO_3

\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3

Molar mass of Na_2CO_3 = 106 g/mole

\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg

Thus, the mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

3 0
4 years ago
Who discovered the electron?
Sedbober [7]
J.J. Thomson discovered the electron  1897
3 0
3 years ago
Behaviorism measures : Question 1 options: observable behaviors only, thoughts and feelings, emotions, childhood trauma.
Svetllana [295]

Answer:

Observable behaviors only.

Explanation:

I just did the session question.

8 0
4 years ago
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