The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants
Answer:
The relative mass of electron is 0.0005
Explanation:
Atoms are the fundamental unit of matter. Every thing in the universe that occupy space and have mass is called matter. we can say that every matter is composed of atoms. while the atom is composed of subatomic particles called electron proton and neutron.
Subatomic particles Relative charge Relative mass
Proton +1 1
Neutron 0 1
Electron -1 0.0005
Electron:
The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.
Symbol = e⁻
Mass= 9.10938356×10⁻³¹ Kg
electrical charge on electron= -1.6022 × 10⁻¹⁹ C
It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.
Proton and Neutron:
An atom consist of positively charged central core (nucleus) that is made up of Proton and neutron. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.
Symbol of proton= P⁺
electrical charge on proton= +1.6022 × 10⁻¹⁹ C
Mass of proton=1.672623×10⁻²⁷ Kg
Symbol of neutron= n⁰
Mass of neutron=1.674929×10⁻²⁷ Kg
electrical charge on neutron= 0
Answer: The ratio of mass of sulfur atom to mass of oxygen atom in sulfur dioxide is 1: 1.
Explanation:
Law of constant proportion states that In a chemical substance the elements are always present in definite proportions by mass. This law is also known as 'Law of definite proportions '.
Mass of 1 atom of sulphur = 32 g
Mass of 1 atom of oxygen = 16 g
Mass of 2 atoms of oxygen =
In formation of , 1 atom of sulfur combines with 2 atoms of oxygen and thus the mass ratio will be 32: 32= 1:1 .
Thus the ratio of mass of sulfur atom to mass of oxygen atom in sulfur dioxide is 1: 1.
Answer:
The correct answers are "They travel slower than P waves", "They result in much ground motion" and " They are produced by P and S waves".
Explanation:
A surface wave can travel through the existing interface between Earth and air, as well as between Earth and water. A clear example of this type of waves are Love and Rayleigh waves. They travel slower than primary waves, produce large movements in the ground and are produced by primary and secondary waves.
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Answer:
Mass = 36.4 ×10⁻³ g
Explanation:
Given data:
Volume of container = 100 mL ( 100/1000 = 0.1 L)
Pressure = 688 mmHg (0.9 atm)
Temperature = 565°C ( 565 + 273 = 838 K)
Mass in grams of nitrogen = ?
Solution:
According to ideal gas equation,
PV = nRT
n = number of moles
P = pressure
R = general gas constant
T = temperature
From this equation we will determine the number of moles and then we we will calculate the mass.
n = PV/RT
n = 0.9 atm × 0.1 L / 0.0821 atm. L / mol.K × 838 K
n = 0.09 / 68.8
n = 0.0013 mol
or
n = 1.3×10⁻³ mol
Mass of nitrogen gas:
Mass = number of moles × molar mass
Mass = 1.3×10⁻³ mol × 28 g/mol
Mass = 36.4 ×10⁻³ g