Answer:
<h3>The answer is 30 cm³</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 180 g
density = 6 g/cm³
We have
We have the final answer as
<h3>30 cm³</h3>
Hope this helps you
Answer:
B, H, E, G, C, D, A, F
Explanation:
The ones closest to the bottom are the oldest
There are 19.5 g Na in 71.4 g NaHCO₃
Calculate the <em>molecular mass of NaHCO₃</em>.
1 Na = 1 × 22.99 u = 22.99 u
1 H = 1 × 1.008 u = 1.008 u
1 C = 1 × 12.01 u = 12.01 u
3 O = 3 × 16.00 u = <u>48.00 u
</u>
TOTAL = 84.008 u
So, there are 22.99 g of Na in 84.008 g NaHCO₃.
∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na
Answer:
Statment 2
Explanation:
This is just an educated guess
Answer:
To calculate the theoretical yield, determine the number of moles of each reactant, in this case the sole reactant ethanol. Convert the 100 g to moles; the molecular weight of ethanol is 46 g/mole, therefore: Since there is only one reactant, it is also the limiting reagent.
Explanation:
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