3 years ago

What do you notice about the elements on the reactant and product side of the equation

2 answers:

4 0

There is the same overall number of atoms of each element on the reactants side as on the products side, they are simply rearranged. Also, mass is conserved as atoms cannot be created or destroyed by a chemical reaction.

Basile [38]3 years ago

4 0

What goes in, must come out. So the elements on the right hand side, are also on the left hand side. Just bonded differently

You might be interested in

Under standard-state conditions, which of the following half-reactions occurs at the cathode during the electrolysis of aqueous

Slav-nsk [51]

Answer:

The following reaction will occur at cathode:

$Ni^{+2}(aq)+2e--->Ni(s)$

Explanation:

The two half reaction during electrolysis of aqueous nickel sulfate will be

a) anode reaction :

Water will undergo oxidation and will evolve oxygen gas at anode as shown in the given reaction:

$2H_{2}O(l) ----> O_{2}(g) + 4H^{+}(aq) + 4e$

b) Cathode reaction: The reduction of Nickel ion will occur by gain of two electrons as shown in the given equation:

$Ni^{+2}(aq)+2e--->Ni(s)$

Thus the overall reaction will be:

$2H_{2}O(l) + 2Ni^{+2}----> O_{2}(g) + 4H^{+}(aq) + 2Ni(s)$

6 0

2 years ago

Which of the following will neutralize an acid?

pochemuha

LiOH is going to neutralize the acid because it’s a base

8 0

2 years ago

True or false? To prepare 20.0 mL of 2.00 M solution of hydrochloric acid from a 10.0 M stock solution, you should take 4.00 mL

Aleksandr-060686 [28]

Sorry I don’t know but o have to answer for pionts

6 0

3 years ago

What would be the correct name for element 119?

Kay [80]

Ununennium I believe

7 0

3 years ago

Sulfur reacts with oxygen to form sulfur dioxide (SO2(g), Delta. Hf = â€"296. 8 kJ/mol) according to the equation below. Upper S

Rus_ich [418]

The enthalpy of this reaction is -296. 8 kJ/mol.

The equation of the reaction is;

S(s) + O2(g) -----> SO2(g)

Recall that the enthalpy of the reaction can be obtained from the formula;

ΔHrxn = ΔHf(products) - ΔHf(reactants)

We know that;

ΔHf S(s) = 0 KJ/mol

ΔHf O2(g) = 0 KJ/mol

ΔHf SO2(g) = -296. 8 kJ/mol

Hence;

ΔHrxn = -296. 8 kJ/mol - [0 KJ/mol + 0 KJ/mol]

ΔHrxn = -296. 8 kJ/mol

Learn more: brainly.com/question/13164491

7 0

2 years ago