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Valentin [98]
3 years ago
11

Please help ASAP- A book has a mass of 5 kg, a baby has a mass of 5 kg. Which one weighs more?

Physics
2 answers:
Sphinxa [80]3 years ago
7 0

Answer:

Same mass

Explanation:

5kg and 5kg are the same that's the explanation

mihalych1998 [28]3 years ago
4 0
They weigh the same.
Weight = mass * gravity
W of the baby = 5 * 9.81
W of the book = 5 * 9.81
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The rare earth elements include
irga5000 [103]
~Hello there!

Your questions: The rare Earth elements include ___________________.

Your answer: There are many Earth elements but some of the rare elements are the following as mentioned:

1) Gadolinium 

2) Holmium 

3) Yttrium 

4) Promethium 

5) Samarium.

Note: These are some of the rare Earth elements, there are MANY rare elements that are found in Earth.

Any questions ^?

Happy Studying!


7 0
3 years ago
The noise from a power mower was measured at 104 dB. The noise level at a rock concert was measured at 121 dB. Find the ratio of
UkoKoshka [18]

Based on the calculations, the ratio of the intensity of Ir to Ip is equal to 50.12.

<h3>How to find the ratio of the intensity?</h3>
  • Let the intensity of the power mower be Ip.
  • Let the intensity of the rock music be Ir.

Mathematically, sound intensity level can be calculated by using this formula:

\beta = 10 log(\frac{I}{I_{ref}} )

<u>Where:</u>

I is the intensity of the sound.

Making I the subject of formula, we have:

I = Io × 10^{\frac{\beta }{10} }

For Ip, we have:

Ip = Io × 10^{\frac{104 }{10} }

Ip = Io × 10^{10.4}

For Ir, we have:

Ir = Io × 10^{\frac{121 }{10} }

Ir = Io × 10^{12.1}

Now, we can find the ratio of the intensity:

Ir/Ip = Io × 10^{12.1}/Io × 10^{10.4}

Ir/Ip = 10^{12.1}/10^{10.4}

Ir/Ip = 10^{12.1 -10.4}

Ir/Ip = 10^{1.7}

Ir/Ip = 50.12.

Read more on sound intensity here: brainly.com/question/17062836

#SPJ1

8 0
2 years ago
Jerry the mouse is running along a straight desert road at a constant velocity of 18 m/s. If a certain Tom cat wants to capture
Kruka [31]

Answer:

a) t = 1.75 s

b) x = 31.5 m

Explanation:

a) The time at which Tom should drop the net can be found using the following equation:

y_{f} = y_{0} + v_{oy}t - \frac{1}{2}gt^{2}

Where:

y_{f}: is the final height = 0

y₀: is the initial height = 15 m

g: is the gravity = 9.81 m/s²

v_{0y}: is the initial vertical velocity of the net = 0 (it is dropped from rest)

0 = 15m - \frac{1}{2}9.81 m/s^{2}*t^{2}

t = \sqrt{\frac{2*15 m}{9.81 m/s^{2}}} = 1.75 s

Hence, Tom should drop the net at 1.75 s before Jerry is under the bridge.

b) We can find the distance at which is Jerry when Tom drops the net as follows:

v = \frac{x}{t}

x = v*t = 18 m/s*1.75 m = 31.5 m

Then, Jerry is at 31.5 meters from the bridge when Jerry drops the net.

I hope it helps you!                                                                    

3 0
3 years ago
Which of the following is not a physical change?
Makovka662 [10]

Answer:

b. Photosynthesis

Explanation:

This because it is an irreversible process.

.

6 0
3 years ago
At one instant of time a rocket is traveling in outer space at 2500m/s and is exhausting fuel at a rate of 100 kg/s. If the spee
lawyer [7]

Thrust is a reaction force described quantitatively by Newton's third law. When a system expels or accelerates mass in one direction, the accelerated mass will cause a force of equal magnitude but opposite direction on that system. Mathematically can be written as,

T = v\frac{dm}{dt}

Here,

v = speed of the exhaust gases measured relative to the rocket.

\frac{dm}{dt}= Rate of change of mass with respect to time

Our values are given as,

v = 1500m/s

\frac{dm}{dt} = 100kg/s

Replacing we have that

T = 1500*100

\therefore T = 1.5*10^5N

7 0
3 years ago
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