To develop this problem it is necessary to apply the concepts related to Sound Intensity.
By definition the intensity is given by the equation
![\beta = 10Log(\frac{I}{I_0})](https://tex.z-dn.net/?f=%5Cbeta%20%3D%2010Log%28%5Cfrac%7BI%7D%7BI_0%7D%29)
Where,
I = Intensity of Sound
= Intensity of Reference
At this case we have that 15 engines produces 15 times the reference intensity, that is
![I= 15I_0](https://tex.z-dn.net/?f=I%3D%2015I_0)
And the total mutual intensity is 100 dB, so we should
![\beta = 100-10*log(\frac{15I_0}{I_0})](https://tex.z-dn.net/?f=%5Cbeta%20%3D%20100-10%2Alog%28%5Cfrac%7B15I_0%7D%7BI_0%7D%29)
![\beta = 100-10*log(15)](https://tex.z-dn.net/?f=%5Cbeta%20%3D%20100-10%2Alog%2815%29)
![\beta = 100-11.76](https://tex.z-dn.net/?f=%5Cbeta%20%3D%20100-11.76)
![\beta = 88.23dB](https://tex.z-dn.net/?f=%5Cbeta%20%3D%2088.23dB)
Therefore each one of these engines produce D. 88dB.
Good for him ! If he's also adhering to a healthy diet, getting plenty of sleep, avoiding substance dependence, and minimizing his stress level, then he's doing everything he can to maximize his chances for a long, healthy, pleasant and rewarding fun life.
Well,
Typically, a substance is under 1 atmosphere of pressure, or 1 atm. More than 1 atm means there is more pressure than that which the earth's atmosphere exerts on an object near the surface of the earth.
If a liquid is given enough energy, and the atmospheric pressure remains constant, the liquid will turn into a gas. In the case of water, it will turn into water vapor at 100 °C. However, if you increase the pressure to greater than 1 atm, the water will be pushed together, keeping it liquid.
Answer:
= 3.87 m/s
Explanation:
Since momentum is conserved, momentum right before and after the boy jumps onto the skateboard should be the same.
Initial momentum = momentum of boy = 43.2 x 4.10 = 177 kg·m/s
Final momentum = momentum of boy and skateboard = (43.2 + 2.50) x v = 45.7v
177 = 45.7v
v = 177 / 45.7 = 3.87 m/s
(Hope this helps can I pls have brainlist (crown)☺️)
<span>v² = u² + 2as </span>
2as = v² - u²
<span>a = (v² - u²) / 2s </span>
<span>a = (20.0² m²/s² - 6.00² m²/s²) / (2 * 50.0 m) </span>
<span>a = (400 m²/s² - 36 m²/s²) / (100 m) </span>
<span>a = (364 m²/s²) / (100 m) </span>
a = 3.64 m/s²