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Andrews [41]
3 years ago
14

What is the percent composition of phosphoric acid (H3PO4)?

Chemistry
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

H3PO4 Mol mass..

= (3 x H1 = 3) + (1 x P31 = 31) + (4 x O16 = 64). = 98g/mol.

a)..Hydrogen: = 3 / 98 = 0.0306 x 100% = 3.06%.

b)..Phosphorus = 31/98 = 0.3162 x 100% = 31.63%.

c)..Oxygen = 64/98 = 0.6531 x 100% = 65.31%.

(Total = 100% H3PO4).

Explanation:

Find the molar mass of all the elements in the compound in grams per mole.

Find the molecular mass of the entire compound.

Divide the component's molar mass by the entire molecular mass.

You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.

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Keq for the reaction below is 2400. If the initial conditions of the reaction are a 1.0 L flask that contains 0.024 mol NO (g),
podryga [215]

Answer:

The answer to your question is it is not at equilibrium, it will move to the products.

Explanation:

Data

Keq = 2400

Volume = 1 L

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moles of O₂ = 2.6

Process

1.- Determine the concentration of reactants and products

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2.- Balanced chemical reaction

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3.- Write the equation for the equilibrium of this reaction

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- Substitution

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-Simplification

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-Result

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Conclusion

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                         1.11 x 10⁻⁴ < 2400

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