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3 years ago

Consider a hypothetical gas which has the following Van der Waals constants:

Chemistry

2 answers:

Igoryamba3 years ago

4 0

Under conditions of very high pressures, the volume would be lower than predicted by the Ideal Gas Law.

According to the kinetic theory of gases, a gas spreads out to fill the volume of the container holding it. Hence a gas does not have a definite volume due to the fact that there is no inter-molecular interaction between gas molecules.

When the gas is subjected to very high pressure, inter-molecular interactions become significant leading to a decrease in the volume of the gas.

Therefore, when subjected to high pressure, the experimental volume would be lower than predicted by the Ideal Gas Law.

Learn more: brainly.com/question/21443108

mr_godi [17]3 years ago

3 0

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D. all of the above.

Explanation:

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4 years ago

The vapor pressure of liquid chloroform, CHCl3, is 100. mm Hg at 283 K. A 0.380 g sample of liquid CHCl3 is placed in a closed,

Katyanochek1 [597]

Answer:

100 mm Hg

Explanation:

From the question we are told that

The vapor pressure of CHCl3, is $P = 100 \ mmHg = \frac{100}{760}= 0.13156 \ atm$

The temperature of CHCl3 is $T = 283 \ K$

The volume of the container is $V_c = 380mL = 380 *10^{-3}\ L$

The temperature of the container is $T_c = 283 \ K$

The mass of CHCl3 is m = 0.380 g

Generally the number of moles of CHCl3 present before evaporation started is mathematically represented as

$n = \frac{m }{M }$

Here M is the molar mass of CHCl3 with the value $M = 119.38 \ g/mol$

=> $n = \frac{ 0.380 }{119.38 }$

=> $n = 0.00318 \ mols$

Generally the number of moles of CHCl3 gas that evaporated is mathematically represented as

$n_g = \frac{PV}{RT}$

Here R is the gas constant with value $R = 0.08206 L \ atm /mol\cdot K$

$n_g = \frac{0.13156* 380 *10^{-3} }{0.08206 * 283}$

$n_g = 0.00215 \ mols$

Given that the number of moles of CHCl3 evaporated is less than the number of moles of CHCl3 initially present , then it mean s that not all the liquid evaporated

At equilibrium the temperature of CHCl3 will be equal to the pressure of air so the pressure at equilibrium is 100 mmHg

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3 years ago

A chemist determined by measurements that 0.050 moles of tin participated in a chemical reaction. Calculate the mass of tin that

stepladder [879]

Answer:

Explanation:

MM of I2 = 2 (127 g) = 254 g/mol

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8 0

3 years ago

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