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lidiya [134]
3 years ago
10

Find the values of​ a, b, and c for which the quadratic equation ax^2 + bx + c = 0 has the solutions 8i and −8i.

Mathematics
1 answer:
ozzi3 years ago
4 0
Work backward:  Multiply out (x-8i) and (x+8i).

The product is x^2 - [64i^2], or x^2 - [-64], or x^2 + 64

This is equivalent to 1x^2 + 0x + 64, and so a=1, b=0 and c=64.
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Pls help i don’t know how to do this
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Answer: \displaystyle\\\frac{2\pi }{3},\ \frac{5\pi }{3}  .

Step-by-step explanation:

\displaystyle\\tan\theta=-\sqrt{3}\ \ \ \  0\leq \theta\leq 2\pi \\\theta =\frac{2\pi }{3}+\pi N\ \ \ (N=0,\ 1,\ 2,\ 3\ ...)\\ N=0\\\theta=\frac{2\pi }{3} +\pi *0\\\theta=\frac{2\pi }{3}\ \ \ \ ( 0\leq \theta\leq 2\pi)\\ N=1\\\theta=\frac{2\pi }{3}+\pi *1 \\\theta=\frac{2\pi }{3} +\pi \\\theta=\frac{2\pi +3\pi }{3} \\\theta=\frac{5\pi }{3} \ \ \ (  0\leq \theta\leq 2\pi)\\

N=2\\\theta=\frac{2\pi }{3}+2\pi \\ \theta=\frac{2\pi +3*2\pi }{3}\\ \theta=\frac{2\pi +6\pi }{3} \\\theta=\frac{8\pi }{3} \\\theta=2\frac{2}{3} \pi \ \ \ \  (\notin0\leq \theta\leq 2\pi).\\

6 0
1 year ago
What factors does 2 have?
Vanyuwa [196]

Answer:

2 and 1

Step-by-step explanation:

2 only has the factors 2 and 1 because it is a prime number.

4 0
3 years ago
ANSWERS QUICKLY PLEASE
marshall27 [118]
It’s an irrational number (can’t be expressed as a fraction with two integers).
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Find the area of the trapezoid shown.<br><br> 56 sq. units<br> 56√3 sq. units<br> 112 sq. units
kolbaska11 [484]

Answer: A.56 sq. units

Step-by-step explanation:

A=( a+b)h/2

(12+16)4/2

(28)2

56

A=56

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2 years ago
Read 2 more answers
What is a irregular concave polygon
Anvisha [2.4K]

Answer:

An irregular polygon is any polygon that is not a regular polygon. It can have sides of any length and each interior angle can be any measure. They can be convex or concave, but all concave polygons are irregular since the interior angles cannot all be the same.

Step-by-step explanation:

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