Answer:
Profit maximising price = 48
Explanation:
Total Cost : C (x) = 8x + 3
Demand Curve : p (x) = 88 − 2x
Total Revenue = p (x). x = x (88 - 2x) = 88x - 2x^2
Profit maximisation is where Marginal Cost (MC) = Marginal Revenue (MR)
MC = d TC / d Q = d (8x + 3) / d x = 8
MR = d TR / d Q = d (88x - 2x^2) / d x = 88 - 4x
Equating MR & MC ,
88 - 4x = 8 , 88 - 8 = 4x
x = 80 / 4 , x = 20
Putting value in demand curve,
p = 88 - 2x = 88 - 2 (20) = 88 - 40
p = 48
Answer:
inventory impairment/cost of good sold (p/l) $500
Explanation:
IAS 2 requires that inventory be initially recognized at cost including cost of purchase and other necessary cost incurred in getting the inventory to the location where it becomes available for sale.
Subsequently, the item of inventory is carried at the lower of cost or net realizable value (NRV).
Quantity Unit Cost Unit NRV Lower of cost/NRV Amount
Model A 100 $100 $ 120 $100 $10,000
Model B 50 $50 $ 40 $40 $2,000
Model C 20 $200 $210 $200 $4,000
Adjustment required = 50 ($50 - $40)
=$500
This posted as
Debit inventory impairment/cost of good sold (p/l) $500
Credit Inventory account $500
D. Demand is greater than supply
Answer:
$69,000
Explanation:
The computation of the operating income would be shown below:
= Buying cost - making cost
where,
Buying cost equals to
= 60,000 × $3
= $180,000
And, the making cost would be
= Variable cost + fixed cost × avoid percentage
= $90,000 + $70,000 × 30%
= $90,000 + $21,000
= $111,000
Now put these values to the above formula
So, the value would equal to
= $180,000 - $111,000
= $69,000
