Answer:
we cant see the data
Step-by-step explanation:
is there an included angle or lengths for now it's unsolvable
Answer:
The answer is "Option A".
Step-by-step explanation:
Please find the complete question in the attached file.
In the given question, the cone and cylinder shapes both have one circular face at least a cone has one, and the cylinder has two common points.
Answer:
total area = 18.28 in.^2
perimeter = 16.28 cm
Step-by-step explanation:
Area:
The total area of the figure is the sim of the area of the rectangle and the area of the semicircle.
total area = LW + (1/2)(pi)r^2
total area = (4 in.)(3 in.) + (1/2)(3.14)(2 in.)^2
total area = 12 in.^2 + 6.28 in.^2
total area = 18.28 in.^2
Perimeter:
The perimeter of the figure is the sum of the lengths of the left side, bottom side, and right side of the rectangle and the circumference of the half circle.
perimeter = 3 cm + 4 cm + 3 cm + (1/2)(pi)d
perimeter = 10 + (1/2)(3.14)(4 cm)
perimeter = 10 + 6.28 cm
perimeter = 16.28 cm
Answer:
Correct answer: QD = 29
Step-by-step explanation:
Given:
QR = 21 half the longer diagonal
RD = 20 half shorter diagonal
QD = ? rhombus side
The diagonals of the rhombus are known to be perpendicular to each other.
We will calculate the side of the rhombus using Pythagorean theorem.
QD² = QR² + RD²
QD² = 21² + 20² = 441 + 400 = 841
QD = √841 = 29
QD = 29
God is with you!!!
