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Fofino [41]
3 years ago
11

How many grams of KNO₃ should be used to prepare 2.00L of a .500 M solution ?

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
4 0
<span>Volume = 2.00 L

Molarity = 0.500 M

M = n / V

0.500 = n / 2.00

n = 0.500 * 2.00

n = 1.0 mole KNO</span>₃<span>

Molar mass KNO</span>₃ = <span>101.1032 g/mol
</span>
1 mole ------ <span>101.1032 g
</span>1.0 mole ------ ?

mass = 1.0 * 101.1032 g / 1

mass = 101.1032 g of KNO₃

hope this helps!

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