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It is D: a spinning cloud of dust...
Answer:
Q = - 8501.99 j
Explanation:
Given data:
Specific heat of Al = 0.902 j/g.°C
Heat lost = ?
Mass of sample = 23.984 g
Initial temperature = 415°C
Final temperature = 22°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 22°C - 415°C
ΔT = -393°C
Q = m.c. ΔT
Q = 23.984 g× 0.902 j/g.°C × -393°C
Q = - 8501.99 j
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