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gulaghasi [49]
3 years ago
8

How might a fact be disproved? Are there some facts that will never be disproved

Chemistry
1 answer:
Paha777 [63]3 years ago
7 0
A fact can be disapproved with further evidence different details. So basically evidence can change a fact!! Hope this helps
You might be interested in
A single 250 gram
Gala2k [10]

2.2 x 10^-2

0.055 / 250 = 0.00022 - This would be 2.2 x 10^-4, but the question is asking for percent, not proportion, so multiply by 100% to get the percentage.

0.00022 * 100% = 0.022% = 2.2 * 10^-2

6 0
3 years ago
In an oven, 7000 kg of limestone are heated to over 900ºC to give lime and carbon dioxide. Assuming all calcium carbonate reacts
kirill [66]

Answer:

3920kg of lime(CaO)   1568m^3 of CO2

Explanation:

I attached the explanation!

also for calculating the volume I assumed Standard Temperature and Pressure(STP).

5 0
3 years ago
1. Do you think that the lightbulb and the Moon spheres are "to scale" compared to the real
Tems11 [23]

Answer:

Yes

Explanation: Had a question like this and I said yes and got it right

3 0
2 years ago
What is the solute and solvent in roundup
olga nikolaevna [1]

Answer:

solute is that we disolve in solvent

solvent is in which we dissolve solute

8 0
3 years ago
When 10.0 grams of sulfur reacts with fluorine gas at a pressure of 2.69 atmosphere in a 5.00 L container at 0.00 degrees Celsiu
Gwar [14]

Answer:

74.1%

Explanation:

Based on the reaction:

S₈ + 16F₂ → 8SF₄

<em>1 mole of sulfur reacts with 16 moles of F₂ to produce 8 moles of SF₄</em>

<em />

To solve this question we must find the moles of each reactant in order to find the moles of SF₄. Thus, we can find the theoretical mass produced. Percent yield is:

Percent yield = Actual yield (25.0g) / Theoretical yield * 100

<em>Moles S₈: 256.52g/mol</em>

10.0g * (1mol / 256.52g) = 0.0390 moles

<em>Moles F₂:</em>

<em>PV = nRT</em>

PV/RT = n

<em>Where P is pressure in atm, V is volume in liters, R is gas constant and T is absolute temperature (0°C = 273.15K)</em>

2.69atm*5.00L / 0.082atmL/molK*273.15K = n

0.600 moles = n

For a complete reaction of 0.600 moles F₂ are required:

0.600mol F₂ * (1mol S₈ / 8 mol F₂) = 0.075 moles S₈

As there are just 0.0390 moles, S₈ is limiting reactant.

The theoretical moles and mass of SF₄ -Molar mass: 108.07g/mol- is:

0.0390 moles S₈ * (8mol SF₄ / 1mol S₈) = 0.312 moles SF₄ * (108.07g) =

33.7g

Percent yield = 25.0g / 33.7g * 100

= 74.1%

6 0
3 years ago
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