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3 years ago

What is the most likely formula for an oxide formed between group a 1 atom x and oxygen

Chemistry

1 answer:

Marizza181 [45]3 years ago

5 0

The most likely formula for an oxide formed between group 1a atom X and oxygen would be

X2O. - X is group 1a atom.

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What is the molar concentration of [H3O+] in a cola that has a pH of 3.120?

ELEN [110]

Answer:

[H₃O⁺] = 7.586×10⁻⁴ M

Explanation:

The pH of a solution is a measure of the molar concentration of H₃O⁺ ions in the solution.

The mathematical expresssion that states the relation between the molar concentration of H₃O⁺ ions and the pH of the solution is:

pH = - log [H₃O⁺].

This is pH is numerically equal to the negative decimal logarithm of the molar concentration of H₃O⁺.

The square brackets are used to indicate molar concentration.

Thus:

pH = - log [H₃O⁺] ← equation

3.120 = -log [H₃O⁺] ← substituting values

- 3.120 = log [H₃O⁺] ← product property of the multiplication

$10^{- 3.120}=[H_3O^+]$ ← antilogarithm property

[H₃O⁺] = 7.586×10⁻⁴ M ← result

8 0

3 years ago

If 420 joules of heat energy is added to 25 grams of water at 25 degrees celcius, what will be the final temperature of the wate

natka813 [3]

Answer:

T2 = 29°C

Explanation:

Given data:

Heat added = 420 j

Mass of water = 25 g

Initial temperature = 25°C

Final temperature = ?

Solution;

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water = 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values.

420 j = 25 g ×4.18 j/g.°C × (Final temperature - initial temperature)

420 j = 25 g ×4.18 j/g.°C × (T2 - 25°C)

420 j = 104.5 j/°C × (T2 - 25°C)

420 j /104.5 j/°C = T2 - 25°C

4°C + 25°C = T2

T2 = 29°C

4 0

4 years ago

Watching the assignment without knowing how to solve the questions is the worst thing to experience hope someone can help with t

frez [133]

Answer:

- 622.5kJ

Explanation:

1) 2NH3 + 3N2O ----> 4N2 + 3H2O ΔH° 1= - 1010kJ

- 3 (N2O + 3H2 ---> N2H4 + H2O ΔH° 2 = - 317 kJ)

2) 2NH3 + 3N2O ----> 4N2 + 3H2O ΔH° 1= - 1010kJ

- 3N2O - 9 H2 ----> - 3N2H4 - 3H2O - 3ΔH° 2 = 3*317 kJ

2NH3 + 3N2H4 --->4N2+9H2, ΔH° 1 - 3*ΔH° 2

2NH3 + 3N2H4 --->4N2+9H2, ΔH° 1 - 3*ΔH° 2

3) -(2NH3 +1/2O2 ---> N2H4 + H2O, ΔH°3 = -143 kJ)

-2NH3 - 1/2O2 ---> - N2H4 - H2O, - ΔH°3 = 143 kJ

2NH3 + 3N2H4 --->4N2+9H2, ΔH° 1 - 3*ΔH° 2

-2NH3 - 1/2O2 ---> - N2H4 - H2O, - ΔH°3 = 143 kJ

4N2H4 + H2O ---> 4N2 + 9H2 + 1/2O2, ΔH° 1 - 3*ΔH° 2 - ΔH°3

H2 + 1/2O2 ---> H2O, ΔH° 4 = - 286 kJ

9*(H2 + 1/2O2 ---> H2O, ΔH° 4 = - 286 kJ)

9H2+ 9/2 O2 ---> 9H2O, 9*ΔH° 4 = 9*(- 286) kJ

4N2H4 + H2O ---> 4N2 + 9H2 + 1/2O2, ΔH° 1 - 3*ΔH° 2 - ΔH°3

9H2+ 9/2 O2 ---> 9H2O, 9*ΔH° 4 = 9*(- 286) kJ

4N2H4 +4O2 --->4N2+8H2O, ΔH° 1 - 3*ΔH° 2 - ΔH°3 + 9*ΔH° 4

1/4*(4N2H4 +4O2 --->4N2+8H2O, ΔH° 1 - 3*ΔH° 2 - ΔH°3 + 9*ΔH° 4

N2H4 +O2 --->N2+2H2O, 1/4( ΔH° 1 - 3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)

N2H4 +O2 --->N2+2,

1/4( ΔH° 1 - 3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)=

=1/4(-1010kJ - 3*(-317kJ) - (-143kJ) + 9*(-286kJ))= - 622.5 kJ

7 0

3 years ago

On the Periodic Table, which elements are predominantly (mostly) gases with low densities?

aliya0001 [1]

I’m sorry if I wasted your time but I think it’s alkali metals but I’m
Not sure

5 0

3 years ago

What is the number of electrons in an atom that has 20 protons and 17 neutrons

Anni [7]

Answer:

Explanation:

Atoms have the same amount of electrons as they have protons. Therefore, if an atoms has 20 protons, it should have 20 electrons.

8 0

4 years ago