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Rudik [331]
3 years ago
11

I don't know any of these Chem 1 questions

Chemistry
1 answer:
Dima020 [189]3 years ago
5 0
N. <span>Therefore, the 1p </span>orbital<span> doesn't exist. In the second shell, both 2s and 2p </span>orbitals<span>exist, as it can have a maximum of 8 electrons. In the third shell, only the 3s, 3p and 3d </span>orbitals<span> exist, as it can hold a maximum of 18 electrons. Therefore, the </span>3f orbitals<span> do not exist.</span>
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Suppose that a TLC plate is spotted with samples 1.0 cm above the bottom of the plate. Select the consequence of inserting the p
Oksi-84 [34.3K]

Answer:

The compounds in the samples will leach into the pool of developing solvent resulting in poor resolution.

Explanation:

The aim of thin layer chromatography is the separation of a mixture. Usually, the stationary phase is spotted with the mixture. A mark is made with a pencil at the point to be spotted.

It is necessary to note that the solvent must be below the spot where the mixture is. This is because, if the solvent is above the spot of the mixture to be separated, the components of the mixture will dissolve away in the solvent resolution in poor separation. This is exactly what will happen when the sample is spotted at 1.0 cm above the bottom when the solvent is 1.2 cm above the bottom.

8 0
3 years ago
Calculate the number of C, H, and O atoms in 1.50 g of glucose, a sugar
DIA [1.3K]
Chemical formula of the glucose: C₆H₁₂O₆

We calculate the molar mass:
atomic mass (C)=12 u
atomic mass (H)=1 u
atomic mass (O)=16 u

atomic weight (C₆H₁₂O₆)=6(12 u)+12(1u)+6(16 u)=72 u+12u+96 u=180 u.
Therefore : 1 mol of glucose will be 180 g
The molar mass would be: 180 g/ mol


2) we calculate the number of moles of 1.5 g.
180 g---------------------1 mol
1.5 g----------------------  x

x=(1.5 g * 1 mol) / 180 g≈8.33*10⁻³ moles

we knows that:
1 mol = 6.022 * 10²³ particles (atoms or molecules)

3)We calculate the number of molecules:

Therefore:
1 mol-----------------------6.022*10²³ molecules of glucose
8.33*10⁻³ moles--------        x

x=(8.33*10⁻³ moles * 6.022*10²³ molecules)/1 mol≈5.0183*10²¹ molecules.

4)We calculate the number of C, H and O atoms:
A molecule of glucose have 6 atoms of C, 12 atoms of H, and 6 atoms of O,
number of atoms of C=(6 atoms/1 molecule)(5.0183*10²¹molecules)≈
3.011*10²²

number of atoms of H=(12 atoms/1 molecule)(5.0183*10²¹ molecules)≈
6.022*10²² .

number of atoms of O=(6 atoms/1 molecule)(5.0183*10²¹ molecules)≈
3.011*10²²

Answer: we have 3.011*10²² atoms of C, 6.022*10²² atoms of H, and 3.011*10²² atoms of O.
4 0
3 years ago
In an effort to try winning World War I, many countries broke previously created treaties and pacts that banned the use of chemi
nadya68 [22]

D the belguim people atacked using it

3 0
3 years ago
If you had .0451 moles of CaCl2, how many grams would you have?
Montano1993 [528]

Answer:

option C

Explanation:

because i took the test

8 0
2 years ago
Why does the study of science have limitations
oksano4ka [1.4K]

Science doesn't make moral judgments, doesn't make aesthetic judgments, doesn't tell you how to use scientific knowledge, doesn't draw conclusions about supernatural explanations. So that's why I think it has limitations.

7 0
3 years ago
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