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Rudik [331]
3 years ago
11

I don't know any of these Chem 1 questions

Chemistry
1 answer:
Dima020 [189]3 years ago
5 0
N. <span>Therefore, the 1p </span>orbital<span> doesn't exist. In the second shell, both 2s and 2p </span>orbitals<span>exist, as it can have a maximum of 8 electrons. In the third shell, only the 3s, 3p and 3d </span>orbitals<span> exist, as it can hold a maximum of 18 electrons. Therefore, the </span>3f orbitals<span> do not exist.</span>
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The volume of 0.6305 kg of a liquid is 0.430 L. What is its density in g/mL
motikmotik

Answer: 1.466 g/mL

Explanation:

\frac{0.6305 \text{kg}}{0.430 \text{L}} \cdot \frac{1000 \text{g}}{1 \text{kg}} \cdot  \frac{1 \text{L}}{1000 \text{mL}} = 1.466 \,\frac{\text{g}}{\text{mL}}

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2 years ago
Describe how changing the particles changed the atom
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Bonds between atoms break and new ones form and energy is either given out or taken in
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The size of the chosen symbols on a graph may be used to indicate the:
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Uncertainty of the data  hope its help you

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2c4H10 +13O2 —&gt;8CO2+10H2O to find how many moles of oxygen would react with 4.3 mol C4H10
Elena-2011 [213]

Answer:

\large\boxed{\text{28 mol of O$_{2}$}}

Explanation:

             2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

n/mol:      4.3  

13 mol of O₂ react with 2 mol of 2C₄H₁₀

\text{Moles of O}_{2} = \text{4.3 mol C$_{4}$H$_{10}$} \times \dfrac{\text{13 mol O}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \textbf{28 mol O}_{2}\\\\\text{The reaction requires $\large\boxed{\textbf{28 mol of O$_{2}$}}$}

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If the distance between two objects of the same mass decreased the force of gravity between them would
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Answer:

The force of gravity between two objects will decrease as the distance between them increases.

Explanation:

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