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xz_007 [3.2K]
3 years ago
15

The act of sticking to other substances

Chemistry
1 answer:
Gwar [14]3 years ago
3 0
This act is called adhesion: the process of water, sticking onto other substances.

Next time, try completing your question.


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if you mixed 72.9g hydrochloric acid(aq) with 150g silver acetate(aq), what would be the limiting reagent?​
horsena [70]

Answer:

                      Silver Acetate would be the Limiting Reagent.

Explanation:

                    The balance chemical equation for the given double displacement reaction is as;

                            HCl + AgC₂H₃O₂ → AgCl + HC₂H₃O₂

Step 1: <u>Calculate Moles of Starting Materials:</u>

Moles of HCl:

                      Moles  =  Mass / M.Mass

                      Moles  =  72.9 g / 36.46

                      Moles =  1.99 moles

Moles of AgC₂H₃O₂:

                      Moles  =  150 g / 166.91 g/mol

                      Moles  =  0.898 moles

Step 2: <u>Find out Limiting reagent as:</u>

According to balance chemical equation.

              1 mole of HCl reacts with  =  1 mole of AgC₂H₃O₂

So,

         1.99 moles of HCl will react with  =  X moles of AgC₂H₃O₂

Solving for X,

                     X =  1.99 mol × 1 mol / 1 mol

                     X =  1.99 mol of AgC₂H₃O₂

Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.

8 0
3 years ago
What is the mass % of iron in Fe(CH3CO2)2<br><br> (Fe=iron=55.85)
Serjik [45]
The mass percentage is 15.1465%.
5 0
3 years ago
Which of the following is correct? Gas atoms subjected to electricity emit bright lines of light. Gas atoms absorb white light a
Dovator [93]
Your answer would be, Gas atoms subjected to the electricity emit bright lines of light.




Hop that helps!!!
5 0
3 years ago
In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is
irga5000 [103]
Answer:
            <span>In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is <u>Hydrogen atom of HBr</u>.

Explanation:
                   In this reaction first of all HBr approaches the triple bond. A Pi Complex (weak inter-molecular interactions) is formed between the two molecules. And the triple bond attacks the partial positive hydrogen atom creating a negative charge on Bromine along with positive charge on itself (Sigma Complex). In second step the negative Bromide attacks the positive carbon of Butyne.</span>
7 0
3 years ago
Please help with any
lys-0071 [83]
10 down: Particle with no charge

Answer: Neutron
3 0
3 years ago
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