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3 years ago

If a metal has a density of 8.9 g/ml, and a volume of 200mls, what is the mass?

Chemistry

1 answer:

drek231 [11]3 years ago

8 0

Answer:

<h3>The answer is 1780 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of metal = 200 mL

density = 8.9 g/mL

We have

mass = 8.9 × 200

We have the final answer as

Hope this helps you

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Which of the following best describes the change in Antarctic temperature from about 440,000 years ago to about 340,000 years ag

Vlada [557]

Answer: С . The temperature increases by about 12°C and then decreases by about 12°C.

Explanation:

Temperatures around the world have been on the rise since the Industrial revolution as humans clog the planet with Carbon Dioxide and other pollutants. This had led to a rise in temperatures that has seen ice levels fall and sea levels rise around the world.

Temperature fluctuations on the other hand are not a new thing. Studies show that in Antarctica temperatures from about 440,000 years ago to about 340,000 years ago increased by 12°C and then decreased by about 12°C.

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3 years ago

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The half-life of plutonium-241 is approximately 13 years. a. How much of a sample weighing 2 g will remain after 70 years? b.

Studentka2010 [4]

Answer: A) 0.0480 grams and B) 56.16 years.

Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.

The formula we use for solving this type of problem is:

$\frac{N}{N_0}=(\frac{1}{2})^n$

where, $N_0$ is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.

$n=T/t_1_/_2$

where, T is the time and $t_1_/_2$ is half life.

A) from given data, $N_0$ = 2 g

T = 70 years

$t_1_/_2$ = 13 years

N= ?

$n=\frac{70years}{13years}$

n = 5.38

$\frac{N}{2g}=(\frac{1}{2})^5^.^3^8$

$\frac{N}{2g}=0.0240$

N = 0.0480 g

So, 0.0480 grams of the substance will be remaining after 70 years.

B) $N_0$ = 2 g

N = 0.1 g

T = ?

Let's first calculate the value of n for this.

$\frac{0.1}{2}=(\frac{1}{2})^n$

$0.05=0.5^n$

Taking log to both sides:

$log0.05=nlog0.5$

$-1.301=n(-0.3010)$

$n=\frac{1.3010}{0.3010}$

n = 4.32

Half life is 13 years, so we can calculate the time as:

$n=T/t_1_/_2$

$T=n*t_1_/_2$

$T=4.32*13years$

T = 56.16 years

So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.

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4 years ago

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A hydrocarbon with general formaul cxhy is burned completely in air yielding 0.18 g of water and 0.44 g of carbon dioxide. Which

Savatey [412]

Answer:

CH2

Explanation:

When a hydrocarbon is burnt in air or oxygen, there are two products only, these are water and carbon iv oxide.

Fuel + Oxygen—-> Water + Carbon iv oxide

We can get the formula through calculations as follows.

From the mass of carbon iv oxide produced, we can get the number of moles of carbon produced. We first divide the mass by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol

The number of moles of carbon iv oxide is 0.44/44 = 0.01

Since there is only one carbon atom in CO2, the number of moles of carbon is same as above I.e 0.01 moles

From the number of moles of water, we can get the number of moles of hydrogen. To get the number of moles of water, we need to divide the mass of water by its molar mass. Its molar mass is 18g/mol. The number of moles here is thus 0.18/18 = 0.01moles

But there are 2 atoms of hydrogen in 1 mole of water and thus, the number of moles of hydrogen is 2 * 0.01= 0.02moles

The empirical formula can be obtained by dividing the number of moles of each by the smallest which is that of 0.01

H = 0.02/0.01 = 2

C = 0.01/0.01 = 1

From the calculations, x = 1 and y = 2

The empirical formula is thus CH2

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4 years ago

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What is locked up carbon dioxide

katen-ka-za [31]

Basically it means carbon dioxide is removed from the atmosphere and is trapped in e.g. calcium carbonate (like shells), rocks, oceans etc.

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3 years ago

Which is the correct answer? (I already tried to do it)

Jet001 [13]

See if it is telling you to add them lol

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3 years ago