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attashe74 [19]
2 years ago
8

using dimensional analysis find the relation between the velocities of transverse waves produced from the vibration of thin homo

geneous string and between the tension in the string and mass per unit length of it.​
Physics
1 answer:
gulaghasi [49]2 years ago
5 0

Answer:

v^2=\frac{T}{M}

where v = transverse wave velocity, T = tension in the string, M = mass per unit length.

Explanation:

Dimensional analysis is where you just look at the units and see how they fit within each other.

In this case, all relationships are made using the MLT comparisons, where M stands for Mass, L stands for Length, and T stands for time.

For example, for velocity, we know the SI unit for velocity is [ms⁻¹] which is L¹T⁻¹, we can do the same thing for tension = [N = Kgms⁻²] = M¹L¹S⁻², and for the mass per unit length which we can think of as [Kgm⁻¹] = M¹L⁻¹.

If you play around a little with the powers, you can find a relationship:

v^2=\frac{T}{M}

since:

[L¹T⁻¹]² = L²T⁻² = M¹L¹T⁻² ÷ M¹L⁻¹ = M¹⁻¹L¹⁻⁽⁻¹⁾T⁻² = M⁰L²T⁻² = L²T⁻²

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Sam drives her scooter 7 kilometres north. She stops for lunch and then drives
Talja [164]

Answer:

1. Distance travelled = 12 km.

2. Displacement = 8.6 km

Explanation:

From the question given above, the following data were obtained:

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance =?

Displacement =?

1. Determination of the distance travelled.

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance (dₜ) =?

dₜ = d₁ + d₂

dₜ = 7 + 5

dₜ = 12 km

2. Determination of the displacement.

In the attached photo, R is the displacement.

We can obtain the value of R by using the pythagoras theory as illustrated below:

R² = 7² + 5²

R² = 49 + 25

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8 0
2 years ago
If both mass and speed are doubled, what happens to its momentum?
puteri [66]

The general formula is:      Momentum = (mass) x (speed)

I never like to just write a bunch of algebra without explaining it.
But in this particular case, there's really not much to say, and
I think the algebra will pretty well explain itself.  I hope so:


Original momentum = (original mass) x (original speed)


New momentum = (2 x original mass) x (2 x original speed)

                           = (2) x (original mass) x (2) x (original speed)

                           = (2) x (2) x (original mass) x (original speed)

                           =  (4) x (original mass) x (original speed)

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3 years ago
1. 1500j of work was done to move a box 20m. What force was applied to the box ?
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Answer:

1. 75N

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Explanation:

1. Work = Force x Distance

we are given that Work = 1,500J and Distance = 20m

hence,

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assuming that gravity, g = 9.81 m/s²

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Potential Energy, PE = 165 x 9.81 x 42 = 67,983 J (=67.98 kJ)

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