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attashe74 [19]
2 years ago
8

using dimensional analysis find the relation between the velocities of transverse waves produced from the vibration of thin homo

geneous string and between the tension in the string and mass per unit length of it.​
Physics
1 answer:
gulaghasi [49]2 years ago
5 0

Answer:

v^2=\frac{T}{M}

where v = transverse wave velocity, T = tension in the string, M = mass per unit length.

Explanation:

Dimensional analysis is where you just look at the units and see how they fit within each other.

In this case, all relationships are made using the MLT comparisons, where M stands for Mass, L stands for Length, and T stands for time.

For example, for velocity, we know the SI unit for velocity is [ms⁻¹] which is L¹T⁻¹, we can do the same thing for tension = [N = Kgms⁻²] = M¹L¹S⁻², and for the mass per unit length which we can think of as [Kgm⁻¹] = M¹L⁻¹.

If you play around a little with the powers, you can find a relationship:

v^2=\frac{T}{M}

since:

[L¹T⁻¹]² = L²T⁻² = M¹L¹T⁻² ÷ M¹L⁻¹ = M¹⁻¹L¹⁻⁽⁻¹⁾T⁻² = M⁰L²T⁻² = L²T⁻²

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2 years ago
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3 years ago
Using the information from Paul Hewitt's Conceptual Development Practice Page 25-1 and the image below, answer the following que
MaRussiya [10]

Answer:

A = 2 cm ,   λ = 8 cm

Explanation:

The amplitude of a wave is the maximum height it has, in this case the height is measured by the vertical ruler,

We are told the balance point is in the reading of 5 cm, that the maximum reading is 3 cm and the Minimum reading is 7 cm. Therefore, the distance from the ends of the ridge to the point of equilibrium is

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6 0
2 years ago
A 6.5 l sample of nitrogen at 25◦c and 1.5 atm is allowed to expand to 13.0 l. the temperature remains constant. what is the fin
ollegr [7]
Since the temperature of the gas remains constant in the process, we can use Boyle's law, which states that for a gas transformation at constant temperature, the product between the gas pressure and its volume is constant:
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In our problem, p_1 = 1.5 atm, V_1 =6.5 L and V_2 =13.0 L, so the final pressure of the gas can be found by re-arranging eq.(1):
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<span>1. 0.75 atm</span> 
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