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3 years ago

A mans walks 200 meter on 20 seconds. What is the man speed?

Physics

2 answers:

coldgirl [10]3 years ago

7 0

I think that the answer is letter C.

SVETLANKA909090 [29]3 years ago

7 0

The answer is (c) i think

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a 50kg person is standing still in ice skates throws their 2.0kg helmet to the right at 25m/s while on a friction less surface.

Roman55 [17]

Answer:

Vp = 1 [m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of the amount of movement. In the same way, analyze the before and after of the actions.

<u>The moment before</u>

The 50kg person is still hold (no movement) with the 2kg helmet

<u>The moment after</u>

The helmet moves at 25[m/s] in one direction, the person moves in the opposite direction, due to the launch of the helmet.

In this way we can apply the principle of conservation of movement, expressing the before and after. To the left we have the before and to the right of the equal sign we have the after.

Σm*V1 = Σm*V

where:

m = total mass = (2 + 50) = 52[kg]

V1 = velocity before the lunch = 0

(50 + 2)*V1 = (25*2) - (Vp*50)

0 = 50 - 50*Vp

50 = 50*Vp

Vp = 1 [m/s]

8 0

3 years ago

the guage pressure in a car tire is 30.0 psi when the air temperature is 0 C as the day warms up and brighten sun shines What is

Viktor [21]

Answer:

$P_2 = 33.297\ psi$

Explanation:

give,

Gauge pressure of car, P₁ = 30 psi

temperature,T₁ = 0° C = 0 + 273 = 273 K

Assuming temperature at the noon = 30° C

T₂ = 30 + 273 = 303 K

Pressure at this temperature, P₂ = ?

Using ideal gas equation

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$

taking volume as in compressible V₁ = V₂

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

$\dfrac{30}{273}=\dfrac{P_2}{303}$

$P_2 = 303\times \dfrac{30}{273}$

$P_2 = 33.297\ psi$

Hence, Pressure of the at 30°C is equal to 33.297 psi.

3 0

3 years ago

A Blu-ray disc is approximately 8 centimeters in diameter. The drive motor of the Blu-ray player is able to rotate up to 10,000

Ray Of Light [21]

Answer:

The question is incomplete. Here is the complete question:

A Blu-ray disc is approximately 8 centimeters in diameter. The drive motor of the Blu-ray player is able to rotate up to 10,000 revolutions per minute, depending on what track is being read. (a) Find the maximum angular speed (in radians per second) of a Blu-ray disc as it rotates. (b) Find the maximum linear speed (in meters per second) of a point on the outermost track as the disc rotates.

Answer:

(a) 1047.2 rad/sec

(b) 41.9 m/s

Explanation: Please see the attachments below

8 0

3 years ago

Read 2 more answers

2-Pema runs

Oxana [17]

Answer:

20 m/s

Explanation:

Distance covered by man =500m

Time taken by man=25 seconds

Speed of man = distance/time

= 500/25

=20 m/s

4 0

3 years ago

Compute VO when Vin = 0.5 V, in two different ways: a) using the equation VO = G (V+-V-) with G = 106; and b) using the Golden R

Mrrafil [7]

Is b because yes thanks

7 0

2 years ago