What is the simplified expression

when 1760 is divided into 14 equal parts the remainder is 10. what is a correct way to write the quotient

Ivanshal [37]

Answer:

125 10/14

Step-by-step explanation:

1,760/14 = 125 r10

- 125 x 14 + 10 = 1,760

You turn the remainder into a fraction using whatever number you divided the main number by. In this case that would be 14.

7 0

3 years ago

Please help: 12x^4(-5/6x^3y^2) If possible, include steps Thanks.

tangare [24]

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Question
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$12x^4(- \frac{5}{6} x^3y^2)$

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Multiply the constant: 12 x (-5/6)
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$-10x^4( x^3y^2)$

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Multiply the x (we add the power together when we multiply)
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$-10x^7y^2$

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Answer: -10x⁷y²
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4 0

3 years ago

The slope of the line graphed

katrin2010 [14]

$\displaystyle\bf\\ \text{\bf The slope = }~~\frac{y_2-y_1}{x_2-x_1}=\frac{4-(-4)}{4-(-1)}=\frac{4+4}{4+1}=\boxed{\bf\frac{8}{5}}$

5 0

4 years ago

Company A makes a large shipment to Company B. Company B can reject the shipment if they can conclude that the proportion of def

boyakko [2]

Answer:

$z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17$

The p value for this case would be given by:

$p_v =P(z>3.17)=0.00076$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

Step-by-step explanation:

Information provided

n=400 represent the random sample taken

X=59 represent number of defectives from the company B

$\hat p=\frac{59}{400}=0.1475$ estimated proportion of defectives from the company B

$p_o=0.1$ is the value to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the true proportion of defectives is higher than 0.1 then the system of hypothesis are.:

Null hypothesis: $p \leq 0.1$

Alternative hypothesis: $p > 0.1$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.1475-0.1}{\sqrt{\frac{0.1(1-0.1)}{400}}}=3.17$

The p value for this case would be given by:

$p_v =P(z>3.17)=0.00076$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 0.1 and then Company B can reject the shipment

8 0

4 years ago

if an ambulance is able to respond to a car accident located 5 miles away in 7 minutes, what is the speed of the ambulance in mi

loris [4]

Answer:

Step-by-step explanation:

7 0

4 years ago