The descriptive term applied to the type of diene represented by 2,4-hexadiene is conjugated diene.
Dienes are compounds which contains two double bonds. These dienes can be non conjugated or conjugated.
Conjugated diene are those compound which have two double bonds joined by a single σ bond. Conjugated dienes can also be called 1,3-diene. To know if diene is conjugated or non conjugated, sp³ hybridization is to b checked and the number of double bonds and single sigma bond is checked.
Conjugated dienes are found in many different molecules. 2,4-hexadiene is a conjugated diene with two carbon-carbon double bonds that are separated by one sigma bond.
The stabilization of dienes by conjugation is better than the aromatic stabilization. Conjugated dienes are more stable than non conjugated or cumulative diene because it has higher electron density of molecules delocalized.
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Water, H₂O, will have the highest melting point.
Explanation:
So here we have listed the hydrides of oxygen, sulphur, selenium and tellurium.
From this elements oxygen have the highest electronegativity and as a consequence the oxigen hydride (water, hydrogen dioxide) it is able to form hydrogen bonds between molecules. So you need more energy to overcome the interactions between molecules in water that for the other compounds.
Water, H₂O, will have the highest melting point between the listed hydrides.
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hydrogen bonds
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The correct answer should be Letter B
0.295 * 203 = 53.885
0.705 * 205 = 144.525
53.885 + 144.525 = 204.41
The relative atomic mass of Thallium is 204.41
Answer:
Explanation:
Given parameters:
pH = 3.50
Unknown:
concentration of [H₃0⁺] = ?
concentration of [OH⁻] = ?
Solution:
In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.
pH = -log₁₀[H₃O⁺]
[H₃O⁺] = inverse log₁₀ (-pH) = 
= 
[H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³
For the [OH⁻]:
we use : pOH = -log₁₀ [OH⁻]
Recall: pOH + pH = 14
pOH = 14 - pH = 14 - 3.5 = 10.5
Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]
[OH⁻] = 
[OH⁻] = 
= 3.2 x 10⁻¹¹moldm⁻³
The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.
