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Nezavi [6.7K]
3 years ago
9

To convert meters per minute to kilometers per hour, which of the conversion factors would be used? Select all that apply. (two

answers)
A. 1km/1,000 m
B. 1,000./1km
C. 1 min/60sec
D. 60min/1hr
---
2. convert 2 liters to gallons. Use the fact that 1 gal. = 3.8 L
A. 22 L = 3.2 gal.
B. 22 L = 5.8 gal.
C. 22 L = 8.4 gal.
D. 22 L = 83.6 gal.
Mathematics
2 answers:
madam [21]3 years ago
7 0

okay well since no one said the answer 1. is A and D and 2. is B

Leno4ka [110]3 years ago
7 0

Answer:

Step-by-step explanation:

Here are the correct answers:

1. B and E

2. B

3. B

CONNECTIONS ACADEMY

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Step-by-step explanation:

5/8

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The rent was increase by 7,5 what will be the new rent price​
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Answer:

Is this the full question?

Step-by-step explanation:

5 0
3 years ago
Can you please answer this question?
liraira [26]
300miles/20sec=?miles/1min
900miles/60sec=?miles/1min
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3 0
3 years ago
Read 2 more answers
Given the isosceles trapezoid below, find AG.<br> Show all the work
Dmitry [639]

We know the width of the rectangle in the middle of the trapezoid is 24 (from the top of the image), so we can subtract that from the bottom width of the trapezoid to get the combined length of the bottom of both triangles.

40 - 24 = 16

Since this is an isosceles trapezoid, both triangle bases are the same length, so we can cut this value in half to get the length of GT and EF

\frac{16}{2} = 8

Finally, we can use the Pythagorean Theorem to find the length of AG:

AG^{2} + GT^{2} = AT^{2}

AG^{2} + 8^{2} = 10^{2}

AG^{2} + 64 = 100

AG^{2} = 36

AG = 6

8 0
2 years ago
If the length of AB is 10 cm from the center and has a length of 12, find the approximate length from the center to CD.​
Lynna [10]

<u>Given</u>–

AB = 12 Cm

CD = 14 Cm

PO = 10 Cm

AP = 1/2 × 12 = 6 Cm

<u>Construction</u>–

Draw NO such that it is the perpendicular bisector of CB.

Hence,

ND = 1/2 × 14 = 7 Cm

To Find,

Measure of NO

<u>Solution</u>,

Here, PO Perpendicular to AB

Hence, APO is a right-angled triangle–

AO² = PO² + AP²

Or, AO² = 10 ² + 6 ²

Or, AO² = 36 + 100

Or, AO = √136 Cm

Or, AO = 11.66 Cm

Also, AO = OD = 11.66 Cm

( Radius of the same circle )

Now, in triangle OND,

OD² = ON² + ND ²

Or, 11.66 ² = ON² + 7²

Or, 136 = ON² + 49

Or, ON ² = 136 – 49

Or, ON ² = 87

Or, ON ² = √87

Or, ON = 9.3 Cm

Therefore, the appropriate length from center to CD is 9.3 Cm.

4 0
3 years ago
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