Answer:
The three consecutive POSITIVE ODD integers are: 3, 5 and 7
Step-by-step explanation:
If x is an integer, then there consecutive positive odd integers are:
x , x + 2, x + 4 are three consecutive integers.
Where
First integer, a = x
Second integer, b = x + 2
Third integer, c = x + 4
We are told to:
Find three consecutive POSITIVE ODD integers such that when you multiply the first and third the result is nine less than six times the second integer.
Hence, this is represented as:
a × c = 6(b) - 9
Where
a = x
b = x + 2
c = x + 4
x (x + 4 ) = 6(x + 2) - 9
x ² + 4x = 6x + 12 - 9
x² +4x - 6x - 12 + 9= 0
x² - 2x - 3 = 0
Factorising
x² +x - 3x - 3 = 0
x (x + 1) -3(x + 1) = 0
(x - 3) (x + 1) = 0
x - 3 = 0
x = 3
x + 1 = 0
x = -1
Since, x cannot be negative for this question, x = 3
First integer, a = x = 3
Solving for:
Second integer, b = x + 2
b = 3 + 2 = 5
Solving for :
Third integer, c = x + 4
c = 3 + 4 = 7
Therefore, the three consecutive POSITIVE ODD integers are: 3, 5 and 7
B) 10
if you plug in 10 for x it will make you multiply 2 time 10 which gives you 20 then subtract 5 which gives you 15
Positive 10 more than -10
Answer:
?
Step-by-step explanation:
By difference I think you mean how far away from? I don't really know what you mean by this but I will try to help.
1/2-4=-3 1/2
2-(-3 1/2)=5 1/2
<u>-3 1/2</u>
5 1/2
Above is a fraction.
I hope that I helped. Sorry if it wasn't the answer you were looking for.