All categories

3 years ago

What is 2/3 divided by 8/9

Mathematics

2 answers:

Genrish500 [490]3 years ago

8 0

2/3 divided by 8/9 is 3/4

Liono4ka [1.6K]3 years ago

4 0

3/4
The answer for 2/3 divided by 8/9 is 3/4

You might be interested in

Ms Feheley buys 9 bottles of eye of Newt for the same price, and also a new couldron for $9.45. She spent $118.89. How much did

scoundrel [369]

See picture for answer and solution steps.

4 0

3 years ago

Read 2 more answers

Write an equation to describe the relationship between the independent variable x and the dependent variable y.

AlexFokin [52]

Answer:

x=y+2

Step-by-step explanation:

4 0

3 years ago

How much does Greg earn per hour? Explain how to determine the unit rate from the table?

Butoxors [25]

Answer:

Well you can already answer that(37)

Step-by-step explanation:

In 3 hours and 30 minutes Greg has earned 64.75 dollars if you take that amount(the amount earned in 3 and a half hours) and divide it by the 3 1/2 hours(the time it took to earn that amount) you get 18.50 which is the amount you earn per half hour since that graph is increasing at 30min. per 18.50 or the amount.

3 0

3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$