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Fudgin [204]
3 years ago
12

the length of time it takes a planet to revolve around the sun is equivalent to witch of the following?

Physics
2 answers:
Marina86 [1]3 years ago
6 0
It really depends on how far or close the planet is from the sun

krok68 [10]3 years ago
6 0

Answer:

The length of its year.

Explanation:

When Earth completes a full rotation, a year has completed. So, the same can be the same for other orbiting planet. The moon for example takes  29.5 days to revolve around the Earth, so one moon year is   29.5 Earth days.

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Help me with this speed thingy I don't have no idea
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3 years ago
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If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude
AveGali [126]

Answer: 1.5×10^10 N/C

Explanation:

E= F/q

Where E= magnitude of the electric field

F= force of attraction

q= charge of the given body

Given F= 6.5×10^-8 N

q= 4.3× 10^-18 C

Therefore, E = 6.5×10 ^-8/ 4.3×10^-18

E = 1.5×10^10 N/C

7 0
3 years ago
A bird flew16 km west in 5 hours, then flew 20 km east in 6 hours. what was the birdâs velocity?
Mademuasel [1]
Solve for Speed: 16+20=36 km in 11 hrs
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4 0
3 years ago
A 403.0-kg copper bar is melted in a smelter. The initial temperature of the copper is 320.0 K. How much heat must the smelter p
aleksklad [387]
The answer is 2.49 x 10^5 KJ. This was obtained (1) use the formula for specific heat to achieve Q or heat then (2) get the energy to melt the copper lastly (3) Subtract both work and the total energy required to completely melt the copper bar is achieved.
7 0
3 years ago
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To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
iren [92.7K]

Answer:

372.3 J/^{\circ}C

Explanation:

First of all, we need to calculate the total energy supplied to the calorimeter.

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V = 3.6 V is the voltage applied

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So, the power delivered is

P=VI=(3.6)(2.6)=9.36 W

Then, this power is delivered for a time of

t = 350 s

Therefore, the energy supplied is

E=Pt=(9.36)(350)=3276 J

Finally, the change in temperature of an object is related to the energy supplied by

E=C\Delta T

where in this problem:

E = 3276 J is the energy supplied

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Solving for C, we find:

C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C

5 0
3 years ago
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