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2 years ago

redacteaza un text in care sa iti exprimi parerea in legaturacurtamentul golegilor din textul oracolul

Physics

1 answer:

Ivahew [28]2 years ago

4 0

Answer:

Seriously I have no idea. I need help with my homework.

Explanation:

I really need help with my homework. Sorry

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two electrons are an angstrom (1x10^-10m) apart. What electrostatic force do they exert on one another?

Irina-Kira [14]

Answer:

2.30 × 10⁻⁸ N if the two electrons are in a vacuum.

Explanation:

The Coulomb's Law gives the size of the electrostatic force $F$ between two charged objects:

$\displaystyle F = -\frac{k\cdot q_1 \cdot q_2}{r^{2}}$ ,

where

$k$ is coulomb's constant. $k = 8.99\times 10^{8}\;\text{N}\cdot\text{m}^{2}\cdot\text{C}^{-2}$ in vacuum.
$q_1$ and $q_2$ are the signed charge of the objects.
$r$ is the distance between the two objects.

For the two electrons:

$q_1 = q_2 = 1.60\times 10^{-19}\;\text{C}$ .
$r = 1\times 10^{-10}\;\text{m}$ .

$\displaystyle F = -\frac{k\cdot q_1 \cdot q_2}{r^{2}} = -\frac{8.99\times 10^{8}\times (1.60\times 10^{-19})^{2}}{(1\times 10^{-10})^{2}} = 2.30\times 10^{-8}\;\text{N}$ .

The sign of $F$ is negative. In other words, the two electrons repel each other since the signs of their charges are the same.

8 0

2 years ago

What kind of light results when the total spectrum of refracted light is recombined? violet green white red?

ElenaW [278]

Hello
The final light will be white. In fact, each color of the visible spectrum is an electromagnetic wave with its own specific frequency and wavelength. White, instead, does not have a specific frequency: it is the sum of all the different wavelengths of the visible spectrum. Therefore, when recombining the spectrum of the refracted light all the different frequencies recombine together, and their sum gives white light.

(edited)

4 0

3 years ago

Which kind of air front forms when a warm air mass meets the area of a cooler air mass?

mihalych1998 [28]

Answer: "a cold front" .
_________________________________

8 0

2 years ago

A projectile is fired with initial speed vo at an angle of 45o above the horizontal. Assume no air resistance.

katrin2010 [14]

Answer:

The correct answer is a

Explanation:

At projectile launch speeds are

X axis vₓ = v₀ = cte

Y axis $v_{y}$ = v_{oy} –gt

The moment is defined as

p = mv

For the x axis

pₓ = mvₓ = m v₀ₓ

As the speed is constant the moment is constant

For the y axis

p_{y} = m v_{y} = m (v_{oy} –gt) = m v_{oy} - m (gt)

Speed changes over time, so the moment also changes over time

Let's examine the answer

i True

ii False. The moment changes with time

The correct answer is a

7 0

3 years ago

A gas, behaving ideally, has a pressure P1 and at a volume V1. The pressure of the gas is changed to P2. Using Avogadro’s, Charl

Bond [772]

Answer:

Boyle's Law

$\therefore P_1.V_1=P_2.V_2$

Explanation:

Given that:

initially:

pressure of gas, $= P_1$

volume of gas, $= V_1$

finally:

pressure of gas, $= P_2$

volume of gas, $= V_2$

To solve for final volume $V_2$

According to Avogadro’s law the volume of an ideal gas is directly proportional to the no. of moles of the gas under a constant temperature and pressure.

According to the Charles' law, at constant pressure the volume of a given mass of an ideal gas is directly proportional to its temperature.

But here we have a change in the pressure of the Gas so we cannot apply Avogadro’s law and Charles' law.

Here nothing is said about the temperature, so we consider the Boyle's Law which states that at constant temperature the volume of a given mass of an ideal gas is inversely proportional to its pressure.

Mathematically:

$P_1\propto \frac{1}{V_1}$

$\Rightarrow P_1.V_1=k\ \rm(constant)$

$\therefore P_1.V_1=P_2.V_2$

5 0

3 years ago