A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After

Question

3 years ago

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A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After

the ice block slides 15.0 m, the force is removed. The work done by the applied force isA 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After the ice block slides 15.0 m, the force is removed. The work done by the applied force is

Physics

1 answer:

Lady bird [3.3K] · Answer 1 · 2022-04-15T04:53:29+03:00

Lady bird [3.3K]3 years ago

6 0

Answer:

Explanation:

work done by applied force

= force x displacement

= 7.6 x 15 m

= 114 J .