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saveliy_v [14]
3 years ago
14

A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After

the ice block slides 15.0 m, the force is removed. The work done by the applied force isA 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of motion. After the ice block slides 15.0 m, the force is removed. The work done by the applied force is
Physics
1 answer:
Lady bird [3.3K]3 years ago
6 0

Answer:

Explanation:

work done by applied force

= force x displacement

= 7.6 x 15 m

= 114 J .

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Jessica has a mass of 55kg she sleds down a hill that has a slope of 32 degrees. what is the component of her weight that is alo
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W = 285.62 N

Explanation:

It is given that,

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We need to find the component of her weight that is along her direction of motion.

The component along her direction of motion is shown in attached figure. It means

W_y=mg\sin\theta\\\\W_y=55\times 9.8\times \sin(32)\\\\W_y=285.62\ N

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A motorbike reaches a speed of 20 m/s over 60m, whilst
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Initial speed = 2√10 m/s

<h3>Further explanation  </h3>

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration  

An equation of uniformly accelerated motion  

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