Answer: a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.
d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.
Explanation:
The options are:
a. Place the object on one side of a lever at a known distance away from the fulcrum. Place known masses on the other side of the fulcrum so that they are also paced on the lever at known distance from the fulcrum. Move the known masses to a known distance such that the lever is in static equilibrium.
b. Place the object on a surface of negligible friction and pull the object horizontally across the surface with a spring scale at a non constant speed such that a motion detector can measure how the objects speed as a function of time changes.
c. Place the object on a surface that provides friction between the object and the surface. Use a surface such that the coefficient of friction between the object and the surface is known. Pull the object horizontally across the surface with a spring scale at a nonconstant speed such that a motion detector can measure how the objects speed as a function of time changes.
d. Place the object on the end of a vertically hanging spring with a known spring constant. Allow the spring to stretch to a new equilibrium position and measure the distance the spring is stretched from its original equilibrium position.
Gravitational mass simply has to do with how the body responds to the force of gravity. From the options given, the correct options are A and D.
For option A, by balancing the torque, the mass can be calculated. Since the known mass and the distance has been given here, the unknown mass can be calculated.
For option D, here the gravitational force can be balanced by the spring force and hence the mass can be calculated.
Answer:
According to the National Cancer Institute, the average cost of a pack of cigarettes is $6.28, which means a pack-a-day habit sets you back $188 per month or $2,292 per year. 1 Ten years of smoking comes with a $22,920 price tag
Explanation:
I hope this helps
<span>B. equal and in opposite directions</span>
Answer:
X = 6910319.7 m
Explanation:
let X be the distance where the acceleration of gravity is 85% of what it is on the surface and g1 be the acceleration of gravity at the surface and g2 be the acceleration of gravity at some distance X above the surface.
on the surface of the earth, the gravitational acceleration is given by:
g1 = GM/(r^2) = [(6.67408×10^-11)(5.972×10^24)]/[(6371×10^3)^2] = 9.82 m/s^2
at X meters above the earth's surface, g2 = 85/100(9.82) = 8.35m/s^2
then:
g2 = GM/(X^2)
X^2 = GM/g2
X = \sqrt{GM/g2}
= \sqrt{(6.67408×10^-11)(5.972×10^24)/ 8.35
= 6910319.7 m
Therefore, the acceleration of gravity becomes 85% of what it is on the surface at 6910319.7 m .
