Answer:
-22.2 m/s²
Explanation:
The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:
(1) 
For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:
(2) 
Solving for time t:

(3) 
The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:
(4) 
Solving equation 4 for acceleration of rocket B:
(5) 
The maximum possible force of static friction between two surfaces is given by:
F = μN
F = max friction force, μ = coefficient of static friction, N = normal force
The normal force N equals the object's weight:
N = mg
m = mass, g = gravitational acceleration
Make a substitution:
F = μmg
Given values:
F = 500N, m = 100kg, g = 9.8m/s²
Plug in and solve for μ:
500 = μ(100)(9.8)
μ = 0.51
Answer:
tanΘ
Explanation:
Let gravitational acceleration be g. When the avalanche starts to occur, the gravity force that is parallel to the slope is the same as friction force.
Gravity force that is parallel to the slope can be written as:
G = mgsinΘ
The friction force is the product of normal force and coefficient:

where normal force N is the gravity in the direction perpendicular to the slope

As stated before, gravity force that is parallel to the slope is the same as friction force:



Answer:
The car traveled the distance before stopping is 90 m.
Explanation:
Given that,
Mass of automobile = 2000 kg
speed = 30 m/s
Braking force = 10000 N
For, The acceleration is
Using newton's formula

Where, f = force
m= mass
a = acceleration
Put the value of F and m into the formula

Negative sing shows the braking force.
It shows the direction of force is opposite of the motion.


For the distance,
Using third equation of motion

Where, v= final velocity
u = initial velocity
a = acceleration
s = stopping distance of car
Put the value in the equation


Hence, The car traveled the distance before stopping is 90 m.