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elena-14-01-66 [18.8K]
3 years ago
6

A student is sitting in a chair and not moving, however, there are forces acting on her. What must be trust about the forces act

ing on the student?
Physics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer: It is trusted that the sum of all forces acting on the student, adds up to zero the student is not moving.

Explanation: the plane they give you that the plane is moving at a constant velocity of 250 m/s this means that the acceleration is zero, we substituted in the formula F=ma which will give us the Force. And knowing that its constant speed, forward force is then equal to the Air resistance. Hence we find the Air resistance force

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Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia
lara31 [8.8K]

Answer:

-22.2 m/s²

Explanation:

The equation for position x for a constant acceleration a, time t and initial velocity v₀, initial position x₀:

(1) x=\frac{1}{2}at^2+v_0t+x_0

For rocket A the initial and final position: x = x₀= 0. Using these values in equation 1 gives:

(2) 0=\frac{1}{2}at^2+v_0t

Solving for time t:

-\frac{1}{2}at^2=v_0t

(3) t=-\frac{2v_0}{a}

The times for both rockets must be equal, since they start and end at the same location. Using equation 3 for rocket A and B gives:

(4) \frac{v_{0A}}{a_A}=\frac{v_{0B}}{a_B}

Solving equation 4 for acceleration of rocket B:

(5) a_B=a_A\frac{v_{0B}}{v_{0A}}

3 0
3 years ago
A force equal to 500 N is required to barely move a 100 kg mass on a horizontal surface. Find the static friction coefficient be
Afina-wow [57]

The maximum possible force of static friction between two surfaces is given by:

F = μN

F = max friction force, μ = coefficient of static friction, N = normal force

The normal force N equals the object's weight:

N = mg

m = mass, g = gravitational acceleration

Make a substitution:

F = μmg

Given values:

F = 500N, m = 100kg, g = 9.8m/s²

Plug in and solve for μ:

500 = μ(100)(9.8)

μ = 0.51

8 0
4 years ago
Reese rides her bike 10 kilometers in 5 hours.Avery rides her bike 15 kilometers in 5 hours. Which girl rides her bike faster?​
ddd [48]
The answer is Avery.
4 0
3 years ago
Read 2 more answers
2. A large pack of snow of mass m sits at the top of a trail at a ski resort. Friction keeps the snow pack in place, but when it
Aleks [24]

Answer:

tanΘ

Explanation:

Let gravitational acceleration be g. When the avalanche starts to occur, the gravity force that is parallel to the slope is the same as friction force.

Gravity force that is parallel to the slope can be written as:

G = mgsinΘ

The friction force is the product of normal force and coefficient:

F_f = N\mu

where normal force N is the gravity in the direction perpendicular to the slope

F_f = \mu mgcos\theta

As stated before, gravity force that is parallel to the slope is the same as friction force:

G = F_f

mgsin\theta = \mu mgcos\theta

\mu = sin\theta / cos\theta = tan\theta

8 0
4 years ago
An automobile of mass 2000 kg moving at 30 m/s is braked suddenly with a constant braking force of 10000 N. How far does the car
saveliy_v [14]

Answer:

The car traveled the distance before stopping is 90 m.

Explanation:

Given that,

Mass of automobile = 2000 kg

speed = 30 m/s

Braking force = 10000 N

For, The acceleration is

Using newton's formula

F = ma

Where, f = force

m= mass

a = acceleration

Put the value of F and m into the formula

-10000 =2000\times a

Negative sing shows the braking force.

It shows the direction of force is opposite of the motion.

a = -\dfrac{10000}{2000}

a=-5\ m/s^2

For the distance,

Using third equation of motion

v^2-u^2=2as

Where, v= final velocity

u = initial velocity

a = acceleration

s = stopping distance of car

Put the value in the equation

0-30^2=2\times(-5)\times s

s = 90\ m

Hence, The car traveled the distance before stopping is 90 m.

6 0
3 years ago
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