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elena-14-01-66 [18.8K]
3 years ago
6

A student is sitting in a chair and not moving, however, there are forces acting on her. What must be trust about the forces act

ing on the student?
Physics
1 answer:
tiny-mole [99]3 years ago
8 0

Answer: It is trusted that the sum of all forces acting on the student, adds up to zero the student is not moving.

Explanation: the plane they give you that the plane is moving at a constant velocity of 250 m/s this means that the acceleration is zero, we substituted in the formula F=ma which will give us the Force. And knowing that its constant speed, forward force is then equal to the Air resistance. Hence we find the Air resistance force

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In our lab experiment on Ohm's law, the power supply is connected to a circuit containing one resistor, and a direct current of
lapo4ka [179]

Answer: (A) 3.0=A

Explanation: In order to explain this problem we have to use the OHM law, given by: V=R*I

Besides, we have to consider the resitance equivalent for a parallel connection. This is given by:

1/Re=1/R1+1/R2

If we connect the same resistance, the equivalent resistance is R/2.

Initlally  the current is 1.5 A when one resistance is connected to the batttery. When a second resistance with the same value is connected in parallel to the battery, we have V=Re*Ifinal= (R/2)*Ifinal

also we know that V=R*Iinitial so Iinitial=V/R

then Ifinal= 2*V/R=2*Iinitial

3 0
3 years ago
Two 2.0-cm-diameter insulating spheres have a 6.60 cm space between them. One sphere is charged to + 76.0 nC , the other to - 30
e-lub [12.9K]

Answer:

5.2\times 10^5N/C

Explanation:

Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.

This can be easily seen if we use Gauss's law, \int{E} \, dA=\frac{Q_{enclosed}}{\epsilon_o}

We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,

E=\frac{1}{4\pi r^2} \frac{Q_{enclosed}}{\epsilon_o}

which is the same as that of a point charge.

In our problem the charges being of opposite signs, the electric field will add up. Therefore,

E_{total}=\frac{1}{4\pi\epsilon_o}\frac{q_1+q_2}{r^2}= (9\times10^9) \frac{(76+30)\times10^{-9}}{((1+3.3)\times10^{-2})^2}N/C =5.2\times10^5N/C

where, r = distance between the center of one sphere to the midpoint (between the 2 spheres)

8 0
3 years ago
Which factor should change when comparing the boiling times of the liquids?
Andru [333]

Answer: B

Explanation:

7 0
3 years ago
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A proton starting from rest travels through a potential of 1.0 kV and then moves into a uniform 0.040-T magnetic field directed
Hatshy [7]

Answer:

0.114m

Explanation:

From the general expression for the radius of the proton's resulting orbit, we have

r=\frac{mv}{qB}

where q is is the charge of the proton 1.6*10^{-19}C

m is the mass of the proton  1.67*10^{-27}kg

B is the magnetic field  0.040T

and v i the speed.

to determine the speed, we use the expression

Kinetic Energy=qV

1/2mv^{2}=qV

where <em>V  </em>is the voltage value i.e 1.0kv

and v is the speed

Hence, from simple rearrangement we have the speed v to be

v=\sqrt{\frac{2Vq}{m}} \\

if we substitute value, we have

v=\sqrt{\frac{2*1000*1.6*10^{-19} }{1.67*10^{-27}}} \\

carrying out careful arithmetic we arrive at

v=4.38*10^{5} m/s.

using the value for the speed in the expression for the radius of the orbit as stated earlier, we have

r=\frac{1.67*10^{-27}*4.38*10^{5}}{1.6*10^{-19}*0.04} \\

r=0.114m

7 0
3 years ago
Why is the answer B and not E?
makkiz [27]

Answer:  B

<u>Explanation:</u>

E shows the direction of the ball but the question asks about the direction of the STICK, which is the opposite of the ball.

8 0
4 years ago
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