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3 years ago

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The frequency of a wave is 1) A) measured in cycles per second. B) measured in hertz (Hz). C) the number of peaks passing by any

point each second. D) equal to the speed of the wave divided by the wavelength of the wave. E) all of the above

1 answer:

7nadin3 [17]3 years ago

6 0

Answer: E) all of the above

Explanation:

Frequency is the number of vibrations in one second. It is also defined as the number of crests that pass a point in a given time.

The frequency and the wavelength has an inverse relationship.

Frequency is measured in cycles per second or Hertz(Hz).

The relationship between wavelength and frequency of the wave follows the equation:

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of the wave

c = speed of light

$\lambda$ = wavelength of the wave

Thus all the given statements are true.

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In midair an M = 145 kg bomb explodes into two pieces of m1 = 115 kg and another, respectively. Before the explosion, the bomb w

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Answer:

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Explanation:

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Before the explosion we have $p_i=m_iv_i=Mv_i$ .

After the explosion we have pieces 1 and 2, so $p_f=m_1v_1+m_2v_2$ .

These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.

Since we know momentum must be conserved we have:

$Mv_i=m_1v_1+m_2v_2$

Which means (since we want $v_2$ and $M=m_1+m_2$ ):

$v_2=\frac{Mv_i-m_1v_1}{m_2}=\frac{Mv_i-m_1v_1}{M-m_1}$

So for our values we have:

$v_2=\frac{(145kg)(24m/s)-(115kg)(65m/s)}{(145kg-115kg)}=-133.17m/s$

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Nuclear reactions produce huge amounts of energy by transforming tiny amounts of matter. Please select the best answer from the

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Answer:

Explanation:

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y = 3610 - 4.9 t²

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A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the h

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Answer:

Speed of lighter ball is 4 m/s.

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Applying the principle of conservation of linear momentum,

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