Answer:
Juno scientific payload includes:
- A gravity/radio science system (Gravity Science)
- A six-wavelength microwave radiometer for atmospheric sounding and composition (MWR)
- A vector magnetometer (MAG)
- Plasma and energetic particle detectors (JADE and JEDI)
- A radio/plasma wave experiment (Waves)
- An ultraviolet imager/spectrometer (UVS)
- An infrared imager/spectrometer (JIRAM)
Explanation:
Each mission of NASA has a specific set of instruments that it uses to perform scientific experiments on the desired heavenly body. In case of Juno, the mission for Jupiter has a series of instruments that would study domains of gravitational forces, magnetic effect, particle detection, radiation detection, UV/IR imaging, and plasma experiments.
 
        
             
        
        
        
Answer:

Explanation:
The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.
Also, we know that the centripetal force of an object describing a circular motion is given by:

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle. 
Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So  and
 and  (Since
 (Since  ). Then, we get:
). Then, we get:

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).
 
        
             
        
        
        
Answer:
the force would increase 4 times more 
Explanation 
more force results more mass or acceleration 
 
        
                    
             
        
        
        
Answer:
4.25 m/s
Explanation:
Force, F = 22 N 
Time, t = 0.029 s
mass, m = 0.15 kg 
initial velocity of the cue ball, u = 0 
Let v be the final velocity of the cue ball. 
Use newton's second law 
Force = rate of change on momentum 
F = m (v - u) / t 
22 = 0.15 ( v - 0) / 0.029 
v = 4.25 m/s 
Thus, the velocity of cue ball after being struck is 4.25 m/s.