Answer:
1681714.28571 N/C
Yes it could exist
Explanation:
m = Mass of housefly = 12 m
q = Charge = 70 pC
g = Acceleration due to gravity = 9.81 m/s²
E = Electric field
When an object accumulates charge it means that it is gaining electrons making it negatively charged. This is the concept of static electricity.
Here, the electric force and the graviational force will balance each other
1681714.28571 N/C of electric field would be required to levitate
The direction of the electric field would be upwards vertically.
In air the critical value of electric field is 
which is more than the critical value of electric field in air. So, the electric field can exist.
Answer:
4.8967m
Explanation:
Given the following data;
M = 0.2kg
∆p = 0.58kgm/s
S(i) = 2.25m
Ratio h/w = 12/75
Firstly, we use conservation of momentum to find the velocity
Therefore, ∆p = MV
0.58kgm/s = 0.2V
V = 0.58/2
V = 2.9m/s
Then, we can use the conservation of energy to solve for maximum height the car can go
E(i) = E(f)
1/2mV² = mgh
Mass cancels out
1/2V² = gh
h = 1/2V²/g = V²/2g
h = (2.9)²/2(9.8)
h = 8.41/19.6 = 0.429m
Since we have gotten the heigh, the next thing is to solve for actual slant of the ramp and initial displacement using similar triangles.
h/w = 0.429/x
X = 0.429×75/12
X = 2.6815
Therefore, by Pythagoreans rule
S(ramp) = √2.68125²+0.429²
S(ramp) = 2.64671
Finally, S(t) = S(ramp) + S(i)
= 2.64671+2.25
= 4.8967m
Assuming that you're given either an initial or final velocity, you can use the following equation and solve for the initial or final velocity.
Vyf² = Vyi² - 2g(y - y₀)
Where,
Vyf² = final velocity
Vyi₂² = initial velocity
g = 9.81 m/s²
(y - y₀) = the change in the distance along the y-axis.
You'll need also determine the positive and negative of your y-axis for your final solution because velocity can be positive or negative based on direction. Lastly, don't forget to square root both sides of your equation for your velocity.
I hope this helps.
