Answer:
non-essential amino acids are produced by the body
Explanation:
The half cell in which the electrode gains electrons is where reduction occurs, and the half cell in which the electrode loses electrons is where oxidation occurs.
<h3><u>What is a Galvanic cell ?</u></h3>
Voltaic or galvanic cells are electrochemical devices that use spontaneous oxidation-reduction events to generate electricity. In order to balance the overall equation and highlight the actual chemical changes, it is frequently advantageous to divide the oxidation-reduction reactions into half-reactions while constructing the equations.
Two half-cells make up most electrochemical cells. The half-cells allow electricity to pass via an external wire by separating the oxidation half-reaction from the reduction half-reaction.
<h3><u>
Oxidation:</u></h3>
The anode is located in one half-cell, which is often shown on the left side of a figure. On the anode, oxidation takes place. In the opposite half-cell, the anode and cathode are linked.
<h3><u>Reduction:</u></h3>
The second half-cell, cathode, which is frequently displayed on a figure's right side. The cathode is where reduction happens. The circuit is completed and current can flow by adding a salt bridge.
To know more about processes in Galvanic cell, refer to:
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Answer:
pH = 13
The higher the pH, the more basic.
Good luck :)
Answer:
Explanation:
we know that 1 km =1000 m and 1 hour =60 min
therefore
239 km/hr =239*1000m/60 min=3983.3 m/min
Answer:
There are 1.287 grams of acetylene collected
Explanation:
Total gas pressure = 909 mmHg
Vapor pressure of water = 20.7 mmHg
Pressure of acetylene = 909 mmHg - 20.7 mmHg = 888.3 mmHg
1mmHg = 1 torr
22 ° C + 273.15 = 295.15 Kelvin
Ideal gas law ⇒ pV = nRT
⇒ with p = pressure of the gas in atm
⇒ with V = volume of the gas in L
⇒ with n = amount of substance of gas ( in moles)
⇒ with R = gas constant, equal to the product of the Boltzmann constant and the Avogadro constant (62.36 L * Torr *K^−1 *mol^−1)
⇒ with T = absolute temperature of the gas (in Kelvin)
888.3 torr * 1.024 L = n * 62.36 L * Torr *K^−1 *mol^−1 * 295.15 K
n = 0.04942 moles of C2H2
Mass of C2H2 = 0.04942 moles x 26.04 g/mole = 1.287 g
There are 1.287 grams of acetylene collected