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o-na [289]
3 years ago
14

Which molecule is a saturated fat ?

Chemistry
2 answers:
True [87]3 years ago
6 0

Found this on the internet, maybe this will help you?

Saturated fat, a fatty acid in which the hydrocarbon molecules have a hydrogen atom on every carbon and thus are fully hydrogenated. (By way of comparison, the hydrocarbon molecules of unsaturated fats have two carbons that share double or triple bonds and are therefore not completely saturated with hydrogen atoms.)

zimovet [89]3 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

A saturated fat is defined as a fat that contains long chains of carbon and hydrogen atoms that contains only single bonds and atleast one carboxylic acid group.

For example, butyric acid, lauric acid etc are saturated fats.

Whereas fats that contain atleast double bond in their carbon and hydrogen chain are known as unsaturated fat.

Thus, we can conclude that out of the given options fat depicted in option (A) is a saturated fat.

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Magnesium reacts steadily with hydrochloric acid
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Magnesium + Hydrocloric acid -> Magnesium chloride + hydrogen

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"Describe to show that the has formed is hydrogen"

I don't know what you mean. I can show the chemical equation though.

Mg(s) + 2 HCl(aq) --> MgCl 2(aq) + H 2(g)

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Is the freezing point of water a physical change or a physical property​
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It is a physical change because this change is reversible and no chemical reaction occurs.

Explanation:

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When glucose is fermented, ethanol is formed together with ………………….
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How much energy must be removed from a 94.4 g sample of benzene (molar mass= 78.11 g/mol) at 322.0 K to solidify the sample and
Kay [80]

Answer : The energy removed must be, 29.4 kJ

Explanation :

The process involved in this problem are :

(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)

The expression used will be:  

Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]

where,

Q = heat released for the reaction = ?

m = mass of benzene = 94.4 g

c_{p,s} = specific heat of solid benzene = 1.51J/g^oC=1.51J/g.K

c_{p,l} = specific heat of liquid benzene = 1.73J/g^oC=1.73J/g.K

\Delta H_{fusion} = enthalpy change for fusion = -9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g

Now put all the given values in the above expression, we get:

Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]

Q=-29427.312J=-29.4kJ

Negative sign indicates that the heat is removed from the system.

Therefore, the energy removed must be, 29.4 kJ

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