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PolarNik [594]
2 years ago
8

At a certain temperature, the solubility of zinc(I) chromate is (7.0x10^-5) M. What is the Ksp?

Chemistry
1 answer:
MaRussiya [10]2 years ago
6 0

Answer:

Ksp = 4.9 E-9

Explanation:

  • S = 7.0 E-5 M
  •        ZrCrO4 ↔ Zr²+  +  CrO4²-

solubility:       S            S             S

⇒ Ksp = [ Zr²+ ] * [ CrO4²- ]

⇒ Ksp = S * S = S²

⇒ Ksp = ( 7.0E-5)²

⇒ Ksp = 4.9E-9

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