Answer:
Part a)
![f_w = f_g = 4.57 \times 10^{14} Hz](https://tex.z-dn.net/?f=f_w%20%3D%20f_g%20%3D%204.57%20%5Ctimes%2010%5E%7B14%7D%20Hz)
Part b)
![\lambda_w = 492 nm](https://tex.z-dn.net/?f=%5Clambda_w%20%3D%20492%20nm)
![\lambda_g = 437.3 nm](https://tex.z-dn.net/?f=%5Clambda_g%20%3D%20437.3%20nm)
Part c)
![v_w = 2.25 \times 10^8 m/s](https://tex.z-dn.net/?f=v_w%20%3D%202.25%20%5Ctimes%2010%5E8%20m%2Fs)
![v_g = 2.0 \times 10^8 m/s](https://tex.z-dn.net/?f=v_g%20%3D%202.0%20%5Ctimes%2010%5E8%20m%2Fs)
Explanation:
Part a)
frequency of light will not change with change in medium but it will depend on the source only
so here frequency of light will remain same in both water and glass and it will be same as that in air
![f = \frac{v}{\lambda}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7Bv%7D%7B%5Clambda%7D)
![f = \frac{3 \times 10^8}{656 \times 10^{-9}}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B3%20%5Ctimes%2010%5E8%7D%7B656%20%5Ctimes%2010%5E%7B-9%7D%7D)
![f = 4.57 \times 10^{14} Hz](https://tex.z-dn.net/?f=f%20%3D%204.57%20%5Ctimes%2010%5E%7B14%7D%20Hz)
Part b)
As we know that the refractive index of water is given as
![\mu_w = 4/3](https://tex.z-dn.net/?f=%5Cmu_w%20%3D%204%2F3)
so the wavelength in the water medium is given as
![\lambda_w = \frac{\lambda}{\mu_w}](https://tex.z-dn.net/?f=%5Clambda_w%20%3D%20%5Cfrac%7B%5Clambda%7D%7B%5Cmu_w%7D)
![\lambda_w = \frac{656 nm}{4/3}](https://tex.z-dn.net/?f=%5Clambda_w%20%3D%20%5Cfrac%7B656%20nm%7D%7B4%2F3%7D)
![\lambda_w = 492 nm](https://tex.z-dn.net/?f=%5Clambda_w%20%3D%20492%20nm)
Similarly the refractive index of glass is given as
![\mu_w = 3/2](https://tex.z-dn.net/?f=%5Cmu_w%20%3D%203%2F2)
so the wavelength in the glass medium is given as
![\lambda_g = \frac{\lambda}{\mu_g}](https://tex.z-dn.net/?f=%5Clambda_g%20%3D%20%5Cfrac%7B%5Clambda%7D%7B%5Cmu_g%7D)
![\lambda_g = \frac{656 nm}{3/2}](https://tex.z-dn.net/?f=%5Clambda_g%20%3D%20%5Cfrac%7B656%20nm%7D%7B3%2F2%7D)
![\lambda_g = 437.3 nm](https://tex.z-dn.net/?f=%5Clambda_g%20%3D%20437.3%20nm)
Part c)
Speed of the wave in water is given as
![v_w = \frac{c}{\mu_w}](https://tex.z-dn.net/?f=v_w%20%3D%20%5Cfrac%7Bc%7D%7B%5Cmu_w%7D)
![v_w = \frac{3 \times 10^8}{4/3}](https://tex.z-dn.net/?f=v_w%20%3D%20%5Cfrac%7B3%20%5Ctimes%2010%5E8%7D%7B4%2F3%7D)
![v_w = 2.25 \times 10^8 m/s](https://tex.z-dn.net/?f=v_w%20%3D%202.25%20%5Ctimes%2010%5E8%20m%2Fs)
Speed of the wave in glass is given as
![v_g = \frac{c}{\mu_g}](https://tex.z-dn.net/?f=v_g%20%3D%20%5Cfrac%7Bc%7D%7B%5Cmu_g%7D)
![v_g = \frac{3 \times 10^8}{3/2}](https://tex.z-dn.net/?f=v_g%20%3D%20%5Cfrac%7B3%20%5Ctimes%2010%5E8%7D%7B3%2F2%7D)
![v_g = 2 \times 10^8 m/s](https://tex.z-dn.net/?f=v_g%20%3D%202%20%5Ctimes%2010%5E8%20m%2Fs)
Answer:
u = - 20 cm
m =![\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D)
Given:
Radius of curvature, R = 10 cm
image distance, v = 4 cm
Solution:
Focal length of the convex mirror, f:
f = ![\frac{R}{2} = \frac{10}{2} = 5 cm](https://tex.z-dn.net/?f=%5Cfrac%7BR%7D%7B2%7D%20%3D%20%5Cfrac%7B10%7D%7B2%7D%20%3D%205%20cm)
Using Lens' maker formula:
![\frac{1}{f} = \frac{1}{u} + \frac{1}{v}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%20%3D%20%5Cfrac%7B1%7D%7Bu%7D%20%2B%20%5Cfrac%7B1%7D%7Bv%7D)
Substitute the given values in the above formula:
![\frac{1}{5} = \frac{1}{u} + \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%20%3D%20%5Cfrac%7B1%7D%7Bu%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D)
![\frac{1}{u} = \frac{1}{5} - \frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bu%7D%20%3D%20%5Cfrac%7B1%7D%7B5%7D%20-%20%5Cfrac%7B1%7D%7B4%7D)
u = - 20 cm
where
u = object distance
Now, magnification is the ratio of image distance to the object distance:
magnification, m =![\frac{|v|}{|u|}](https://tex.z-dn.net/?f=%5Cfrac%7B%7Cv%7C%7D%7B%7Cu%7C%7D)
magnification, m =![\frac{|4|}{|-20|}](https://tex.z-dn.net/?f=%5Cfrac%7B%7C4%7C%7D%7B%7C-20%7C%7D)
m =![\frac{4}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B20%7D)
m =![\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D)
Answer:
because
Explanation:
streasm dont flow horizontal because if it did then that would be breaking all laws of physics and we know that what goes up must com down but water cant flow upstream only down if it does flow horizontally then it would either be between two hills or in a plains