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melamori03 [73]
3 years ago
7

Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B

's index of refraction is determined to be 1.333. Knowing this information, which of the following must be true? A. Light can pass through Object A faster than it can pass through Object B.
B. The optical density of Object A is lower than the optical density of Object B.
C. Light can pass through Object B faster than it can pass through Object A.
D. The optical density of Object B is higher than the optical density of Object A.
Physics
2 answers:
Slav-nsk [51]3 years ago
4 0

The correct answer is

C. Light can pass through Object B faster than it can pass through Object A.

In fact, the index of refraction of a material is defined as:

n=\frac{c}{v}

where c is the speed of light in vacuum and v is the speed of light in the material. Rearranging the equation, we can write the speed of light in the material as:

v=\frac{c}{n}

So we that, the smaller the refractive index n, the greater the speed of light in the material, v. In this problem, object B has lower refractive index than object A, so light travels faster in object B.

zlopas [31]3 years ago
3 0
<span>In the question "Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B's index of refraction is determined to be 1.333. Knowing this information, which of the following must be true? A. Light can pass through Object A faster than it can pass through Object B." The correct answer is "Light can pass through Object B faster than it can pass through object A." (option C) The refractive index is a ratio of the speed of light in a medium relative to its speed in a vacuum. The refractive index of any other medium is defined relative to the refractive index of a vacuum, which is assigned a value of 1. Thus, a refractive index of 1.33 for water means that light travels 1.33 times faster in a vacuum than in water.</span>
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kykrilka [37]
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s=1 cm=0.01 m
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t= \frac{S}{v}= \frac{0.01 m}{343 m/s}=2.9 \cdot 10^{-5} s

Now we want to find how far the light travels during this time. Light travels at speed c=3 \cdot 10^8 m/s, therefore the distance it covers during this time is
S=ct = (3 \cdot 10^8 m/s)(2.9 \cdot 10^{-5} s)=8700 m
8 0
3 years ago
A 3.0 m tall, 40 cm diameter concrete column supports a 235,000 kg load. by how much is the column compressed? assume young's mo
statuscvo [17]
The Young modulus E is given by:
E= \frac{F L_0}{A \Delta L}
where 
F is the force applied
A is the cross-sectional area perpendicular to the force applied
L_0 is the initial length of the object
\Delta L is the increase (or decrease) in length of the object.

In our problem, L_0 = 3.0 m is the initial length of the column, E=3.0 \cdot 10^{10}N/m^2 is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:
r= \frac{d}{2}= \frac{40 cm}{2}=20 cm=0.2 m
and the cross-sectional area is
A=\pi r^2 = \pi (0.20 m)^2=0.126 m^2
The force applied to the column is the weight of the load:
W=mg=(235000 kg)(9.81 m/s^2)=2.305 \cdot 10^6 N

Now we have everything to calculate the compression of the column:
\Delta L =  \frac{F L_0}{EA}= \frac{(2.305\cdot 10^6 N)(3.0 m)}{(3.0\cdot 10^{10}N/m^2)(0.126 m^2)} =1.83\cdot 10^{-3}m
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3 0
3 years ago
Read 2 more answers
A 0.050 kg bullet strikes a 5.0 kg stationary wooden block and embeds itself in the block. The block and the bullet fly off toge
natka813 [3]

Answer: 909 m/s

Explanation:

Given

Mass of the bullet, m1 = 0.05 kg

Mass of the wooden block, m2 = 5 kg

Final velocities of the block and bullet, v = 9 m/s

Initial velocity of the bullet v1 = ? m/s

From the question, we would notice that there is just an object (i.e the bullet) moving before the collision. Also, even after the collision between the bullet and wood, the bullet and the wood would move as one object. Thus, we would use the conservation of momentum to solve

m1v1 = (m1 + m2) v, on substituting, we have

0.05 * v1 = (0.05 + 5) * 9

0.05 * v1 = 5.05 * 9

0.05 * v1 = 45.45

v1 = 45.45 / 0.05

v1 = 909 m/s

Thus, the original velocity of the bullet was 909 m/s

3 0
3 years ago
Help with this question
Alina [70]

Answer:

D and B.

Explanation:

The wavelength must be taken from the same corresponding point. D and B are both at the crests of a wave, with no other crests in between, which means the distance between them is equal to one wavelength.

3 0
2 years ago
Have properties that are in between metals and nonmetals.
andrew-mc [135]

Answer:

metalloids

Explanation:

metalloids are also known as semiconductors. they are the ones that are between metals and non metals

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