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melamori03 [73]
3 years ago
7

Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B

's index of refraction is determined to be 1.333. Knowing this information, which of the following must be true? A. Light can pass through Object A faster than it can pass through Object B.
B. The optical density of Object A is lower than the optical density of Object B.
C. Light can pass through Object B faster than it can pass through Object A.
D. The optical density of Object B is higher than the optical density of Object A.
Physics
2 answers:
Slav-nsk [51]3 years ago
4 0

The correct answer is

C. Light can pass through Object B faster than it can pass through Object A.

In fact, the index of refraction of a material is defined as:

n=\frac{c}{v}

where c is the speed of light in vacuum and v is the speed of light in the material. Rearranging the equation, we can write the speed of light in the material as:

v=\frac{c}{n}

So we that, the smaller the refractive index n, the greater the speed of light in the material, v. In this problem, object B has lower refractive index than object A, so light travels faster in object B.

zlopas [31]3 years ago
3 0
<span>In the question "Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B's index of refraction is determined to be 1.333. Knowing this information, which of the following must be true? A. Light can pass through Object A faster than it can pass through Object B." The correct answer is "Light can pass through Object B faster than it can pass through object A." (option C) The refractive index is a ratio of the speed of light in a medium relative to its speed in a vacuum. The refractive index of any other medium is defined relative to the refractive index of a vacuum, which is assigned a value of 1. Thus, a refractive index of 1.33 for water means that light travels 1.33 times faster in a vacuum than in water.</span>
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A 5.0 V battery contains 775 C of charge. How much electricity energy can it produce?
KatRina [158]

Answer:

3875J

Explanation:

Energy is defined as the power × time

And it's defined as

Power = IV - I- current and V- voltage

Now quantity of electricity; Q = I × t

Where I is current and t is time

Now Energy = I ×V×t = V× I×t = V× Q;

where Q is quantity of electricity 775C and V is 5.0volt

Hence 775 × (5) =3875J

7 0
3 years ago
7. Katie and her best friend Liam play tennis every Saturday morning. When Katie serves the ball to Liam, it
KIM [24]

a. 4.52 m/s south

Velocity is a vector, whose magnitude is defined as the ratio between the displacement of the object and the time taken for the displacement to occur:

v=\frac{d}{t}

where

d is the displacement

t is the time

Velocity is a vector, so it also has a direction, which corresponds to that of the displacement.

For the ball in this problem,

d = 9.5 m south

t = 2.1 s

Substituting, we find:

v=\frac{9.5}{2.1}=4.52 m/s

and the directiion is the same as the displacement (south).

b. 4.52 m/s north

For this part, we must keep in mind that the speed is the magnitude of the velocity; however, speed is a scalar, so it does not have a direction.

Here we are told that the tennis ball travels at constant speed, so on its way back from Liam to Katie the ball's velocity is still the same as before, therefore

|v| = 4.52 m/s

However, this time the direction is opposite to before, since the ball is travelling in the opposite direction.

Therefore, the ball's velocity when Liam returns Katie's service is

4.52 m/s north

8 0
3 years ago
1) Subatomic particles called muons can be created in the upper atmosphere by collisions of cosmic rays (energetic particles com
Vsevolod [243]

Answer and explanation:

A.

Muon travelled straight down towards the earth. Therefore the tree moves up in the rest frame of muon (option a)

B.

In muon rest frame it travels Zero meters

C.

Distance, d = Velocity, v * Time, s

where, v = 0.9c = 0.9 \times 8 \times 10^8 , s = 2.2 \mu s

d = 0.9 \times 3 \times 10^8 \times 2.2 \times 10^{-6}\\\\d = 594m

D.

Distance from the top of the mountain to the tree is the same as the distance travelled by the tree in the muons rest frame

that is same as in part C which is 594m

E.

Using lorentz contraction

In the rest frame of someone standing on the mountain

the distance is given by

d' = \frac{d}{\gamma} = d\sqrt{1 - \frac{v^2}{c^2}}, where, \frac{1}{\gamma}= \sqrt{1 - \frac{v^2}{c^2}}

d' = 594\sqrt{1 - \frac{(0.9c)^2}{c^2}}

d' = 594\sqrt{1 - 0.81}

d' = 594 \times 0.4359

d' = 258.92m

F.

in the rest frame of someone standing on the mountain,

muon moves straight down

3 0
3 years ago
Uranium-235 undergoes fission, forming krypton-92, barium-141, and 3
Ahat [919]

Answer:

C

Explanation:

Some of the mass

8 0
2 years ago
Read 2 more answers
CHEGG You have two pipes, having the same elevation, connected to each other that transport water. The given density of water is
Yakvenalex [24]

Answer:

P = 0.6814 MPa

Explanation:

For this exercise we must use the Betuliano relation

      P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ rho v₂² + rho g y₂

where we use the subscript 1 for the first pipe and the subscript 2 for the second pipe

indicate that the two pipes are at the same level therefore

        y₁ = y₂

       P₂ = P₁ + ½ ro (v₁² - v₂²)

let's calculate

       P₂ = 13,785 10⁵ + ½ 997 (41,221² - 55,654²)

       P₂ = (13.785 - 6.97) 105

       P₂ = 6.814 10⁵ Pa

let's reduce to Mpa

       P₂ = 6.814 10⁵ Pa (1 MPa / 10⁶ Pa)

       P₂ = 6.814 10-1 MPa

       P = 0.6814 MPa

3 0
2 years ago
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