Answer:
20573.67N
Explanation:
Given;
mass (m) of the car = 2130kg
angle of inclination Θ = 15⁰
The normal force (F) on the car is given by
F = mgcosΘ
where g is the acceleration due to gravity.
Taking g as 10
and substituting the values of m and Θ into the equation. We have;
F = 2130 x 10 x cos 15⁰
F = 2130 x 10 x 0.9659
F = 20573.67N
Therefore the normal force on the car is 20573.67N
Planet Y has rotated by 135.5° through during this time.
To find the answer, we need to know about the relation between angle and radius of orbit.
<h3>What's the expression of angle in terms of radius?</h3>
- Angle= arc/radius
- As arc = orbital velocity × time,
angle= (orbital velocity × time)/radius
- Orbital velocity= √(GM/radius), G= gravitational constant and M = mass of sun
- So, angle = (√(GM)× time)/radius^3/2
<h3>What's is the angle rotated by planet Y after 5 years, if ratio of the radius of orbit of planet X and Y is 4:3 and planet X is rotated by 88°?</h3>
- Let Ф₁= angle rotated by planet Y, Ф₂= angle rotated by planet X
- As time = 5 years ( a constant)
- Ф₁/Ф₂= (radius of planet X / radius of planet Y)^(3/2)
- Ф₁= (radius of planet X / radius of planet Y)^(3/2) × Ф₂
= (4/3)^(3/2) × 88°
= 135.5°
Thus, we can conclude that Planet Y has rotated by 135.5° through during this time.
Learn more about the orbital velocity here:
brainly.com/question/22247460
#SPJ1
Answer:
The work done by Joel is greater than the work done by Jerry.
Explanation:
Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

Where:
- Work, measured in joules.
- Force exerted on the object, measured in newtons.
- Travelled distance by the object, measured in meters.
During the first 10 minutes, the net work exerted on the object is zero. That is:





In exchange, the net work in the next 5 minutes is the work done by Joel on the object:


Hence, the work done by Joel is greater than the work done by Jerry.
Answer:
1.117935:1
Explanation:
Since the wires are of the same material, they will have the same resistivity
.
The cross-sectional area of the of a wire is given by;

where d is the diameter of the wire.
Also, the relationship between resistance R, cross-sectional area A and length l of a wire is given as follows;

Since the resistivity same for both wires, say wire 1 and wire 2, we can wreite the following;

Hence from eqaution (3), the ration of wire 1 to 2 is expressed as;

Given;


We then use equation (1) to fine the ratio of the area
to 
bearing in mind that 
This ratio gives 0.8281. Substituting this into equation (5), we get the following;
