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Klio2033 [76]
3 years ago
8

How are forest fires beneficial to conifers like Jack Pines? a. Jack pine seeds are protected by forest fires. b. Pine cones are

carried on the winds produced by forest fires. c. Forest fires release the seeds stored in Jack pine cones. d. All of the above.
Physics
2 answers:
Gre4nikov [31]3 years ago
5 0
C. Forrest Fires release the seeds stored in Jack Pines
In-s [12.5K]3 years ago
5 0

Answer: c. Forest fires release the seeds stored in Jack pine cones.

Fire ecology is a scientific discipline that deals with the natural processes that involves fire in an ecosystem and in the ecological effects. Fire in the ecosystem either generates naturally or intentionally by humans. The fire generated naturally is useful in the forests ecosystem, especially forests with coniferous trees. The trees exhibit special adaptation, which involves the release of seeds from the cones by the aid of fire. The naturally generated fires melts the resin covering the cones and helps in the release of seeds from these cones of coniferous trees such as pine.

Hence, forest fires release the seeds stored in Jack pine cones is the correct option.

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Oksanka [162]
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7 0
3 years ago
NEEED HELP!!!
Amanda [17]

Answer:

The correct choice is A. Yes, the more exercise the better.

5 0
2 years ago
A student pulls a cart across the floor with a force of 45 N. If the cart travels 10 m, how much work does the cart do on the st
bixtya [17]
I'm assuming we're applying the standard Integral form of the calculation of work. The solution is provided in the image.  

6 0
3 years ago
HELP PLEASE 20 POINTS SHOW WORK, ALL EQUATIONS
nataly862011 [7]

Answer:

s = 3 m

Explanation:

Let t be the time the accelerating car starts.

Let's assume the vehicles are point masses so that "passing" takes no time.

the position of the constant velocity and accelerating vehicles are

s = vt = 40(t + 2)  cm

s = ½at² = ½(20)(t)² cm

they pass when their distance is the same

½(20)(t)² = 40(t + 2)

10t² = 40t + 80

0 = 10t² - 40t - 80

0 = t² - 4t - 8

t = (4±√(4² - 4(1)(-8))) / 2(1)

t = (4± 6.928) / 2  ignore the negative time as it has not occurred yet.

t = 5.464 s

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300 cm when rounded to the single significant digit of the question numerals.

7 0
3 years ago
The work done to compress a spring with a force constant of 290.0 N/m a total of 12.3 mm is: a) 3.57 J b) 1.78 J c) 0.0219 J d)
iren2701 [21]

Answer:

Work done, W = 0.0219 J

Explanation:

Given that,

Force constant of the spring, k = 290 N/m

Compression in the spring, x = 12.3 mm = 0.0123 m

We need to find the work done to compress a spring. The work done in this way is given by :

W=\dfrac{1}{2}kx^2

W=\dfrac{1}{2}\times 290\times (0.0123)^2

W = 0.0219 J

So, the work done by the spring is 0.0219 joules. Hence, this is the required solution.

7 0
4 years ago
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