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Klio2033 [76]
3 years ago
8

How are forest fires beneficial to conifers like Jack Pines? a. Jack pine seeds are protected by forest fires. b. Pine cones are

carried on the winds produced by forest fires. c. Forest fires release the seeds stored in Jack pine cones. d. All of the above.
Physics
2 answers:
Gre4nikov [31]3 years ago
5 0
C. Forrest Fires release the seeds stored in Jack Pines
In-s [12.5K]3 years ago
5 0

Answer: c. Forest fires release the seeds stored in Jack pine cones.

Fire ecology is a scientific discipline that deals with the natural processes that involves fire in an ecosystem and in the ecological effects. Fire in the ecosystem either generates naturally or intentionally by humans. The fire generated naturally is useful in the forests ecosystem, especially forests with coniferous trees. The trees exhibit special adaptation, which involves the release of seeds from the cones by the aid of fire. The naturally generated fires melts the resin covering the cones and helps in the release of seeds from these cones of coniferous trees such as pine.

Hence, forest fires release the seeds stored in Jack pine cones is the correct option.

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Convert 66.2 mi/h to m/s. 1 mi = 1609 m.<br> Answer in units of m/s.
Kryger [21]

Answer:

Explanation:

66.2mi/h to m/s

\frac{1609m}{1mi}×\frac{66.2mi}{1h}×\frac{1h}{60min}×\frac{1min}{60s}

  1. mi will go with mi
  2. h with h
  3. min with min
  4. m/s is left

\frac{1609*66.2}{60*60}= 29.58772222

Pls make sure of the way of solving to be sure...

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Why would citizens need to be wary of debris on the road?
Feliz [49]
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8 0
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What would happen if a bird was a vulture riding on a zebra's back? How would it affect the relationship?
OLEGan [10]
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6 0
4 years ago
A foam cup with negligible specific heat is used as a calorimeter. If you mix 175 g of water at 20.0°C and 125 g of water at 95.
lidiya [134]

Answer:

T = 51.25°C

Explanation:

Applying the law of conservation of energy, we get:

where,

m₁ = mass of cold water = 175 g

m₂ = mass of hot water = 125 g

T = Final temperature of the mixture = ?

Therefore,

(175\ g)(T-20^oC) = (125\ g)(95^oC-T)\\\\T-20^oC = (0.7143)(95^oC-T)\\\\T(1+0.7143) = 20^oC+67.86^oC\\\\T = \frac{87.86^oC}{1.7143}

<u>T = 51.25°C</u>

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FinnZ [79.3K]
Change in thermal energy = mass × specific heat capacity × change in temperature.
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6 0
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