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Klio2033 [76]
3 years ago
8

How are forest fires beneficial to conifers like Jack Pines? a. Jack pine seeds are protected by forest fires. b. Pine cones are

carried on the winds produced by forest fires. c. Forest fires release the seeds stored in Jack pine cones. d. All of the above.
Physics
2 answers:
Gre4nikov [31]3 years ago
5 0
C. Forrest Fires release the seeds stored in Jack Pines
In-s [12.5K]3 years ago
5 0

Answer: c. Forest fires release the seeds stored in Jack pine cones.

Fire ecology is a scientific discipline that deals with the natural processes that involves fire in an ecosystem and in the ecological effects. Fire in the ecosystem either generates naturally or intentionally by humans. The fire generated naturally is useful in the forests ecosystem, especially forests with coniferous trees. The trees exhibit special adaptation, which involves the release of seeds from the cones by the aid of fire. The naturally generated fires melts the resin covering the cones and helps in the release of seeds from these cones of coniferous trees such as pine.

Hence, forest fires release the seeds stored in Jack pine cones is the correct option.

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What statement best explains their findings? A) The downward force of gravity is less on the notecard because it has less mass.
inysia [295]

Answer:

C) The upward force of air resistance is greater with the note card causing it to reach the ground slower.

3 0
3 years ago
In a mail-sorting facility, a 2.50-kg package slides down an inclined plane that makes an angle of 20.0° with the horizontal. Th
lawyer [7]

Answer:

The coefficient of kinetic friction is 0.382.

Explanation:

Given:

Angle of inclination is, \theta=20.0°

Mass of package is, m=2.50\ kg

Initial speed of package is, u=2.00\ m/s

Final speed of the package at the bottom is, v=0\ m/s

Distance of travel along the incline is, d=12.0\ m

Acceleration due to gravity is, g=9.8\ m/s^2

Let the coefficient of kinetic friction be \mu.

Now, the frictional force will be acting along the incline but in the direction opposite to the direction of motion.

So, the net acceleration acting on the package will be up the incline and is equal to:

a=\mu g\cos\theta-g\sin\theta ----------------- 1

Now, using equation of motion, we have:

v^2-u^2=2ad\\\\0-(2.00)^2=2a(12.0)

Solving for 'a', we get:

-4.00=24.0a\\\\a=-\frac{4}{24}=-\frac{1}{6}\ m/s^2

Now, plug in the value of 'a' in equation (1). This gives,

\mu g\cos\theta-g\sin\theta=\frac{1}{6} ( Neglecting negative sign)

Plug in all the given values and solve for \mu. This gives,

9.8(-sin(20)+\mu cos(20))=\frac{1}{6}\\\\-0.342+\mu\times 0.94=0.017\\\\0.94\mu=0.342+0.017\\\\0.94\mu=0.359\\\\\mu=\frac{0.359}{0.94}=0.382

Therefore, the coefficient of kinetic friction is 0.382.

5 0
4 years ago
A solenoid coil with 22 turns of wire is wound tightly around another coil with 340 turns. The inner solenoid is 25.0 cm long an
LUCKY_DIMON [66]

Answer:

a) 1.34*10^-8 W

b) 1.18*10^-5 H

c) 20mV

Explanation:

a) To find the average magnetic flux trough the inner solenoid you the following formula:

\Phi_B=BA=\mu_oNIA

mu_o: magnetic permeability of vacuum = 4pi*10^-7 T/A

N: turns of the solenoid = 340

I: current of the inner solenoid = 0.100A

A: area of the inner solenoid = pi*r^2

r: radius of the inner solenoid = 2.00cm/2=1.00cm=10^-2m

You calculate the area and then replace the values of N, I, mu_o and A to find the magnetic flux:

A=\pi(10^{-2}m)^2=3.141510^{-4}m^2\\\Phi_B=(4\pi*10^{-7}T/A)(340)(0.100A)(3.1415*10^{-4}m^2)=1.34*10^{-8}W\\

the magnetic flux is 1.34*10^{-8}W

b) the mutual inductance is given by:

M=\mu_o N_1 N_2 \frac{A_2}{l}

N1: turns of the outer solenoid = 22

N2: turns of the inner solenoid

A_2: area of the inner solenoid

l: length of the solenoids = 25.0cm=0.25m

by replacing all these values you obtain:

M=(4\pi*10^{-7}T/A)(340)(22)\frac{3.14*10^{-4}m^2}{0.25m}=1.18*10^{-5}H

the mutual inductance is 1.18*10^{-5}H

c) the emf induced can be computed by using the mutual inductance and the change in the current of the inner solenoid:

\epsilon_1=M\frac{dI_2}{dt}

by replacing you obtain:

\epsilon_1=(1.18*10^{-5}H)(1700A/s)=0.02V=20mV

the emf is 20mV

7 0
4 years ago
Read 2 more answers
In three to five sentences, identify two components of the control subsystem of a vehicle, and use them to explain why driving c
vredina [299]

A car is built from various subsystems. If these subsystems are not working properly it is dangerous because it can cause a serious traffic accident.

<h3>What subsystems do cars have?</h3>

When you're testing the build of a car, you have to check its many subsystems:

  • the battery
  • the engine
  • the cabin
  • the thermal-management system
  • the gearbox
  • the chassis
  • the suspension

<h3>Why is a car with damaged subsystems dangerous?</h3>

The subsystems of a car are very important components that allow the proper functioning of the car. These subsystems work synchronously making the car work properly.

However, if one of these subsystems is not working properly it could cause a malfunction that could lead to a traffic accident.

Learn more about cars in: brainly.com/question/11733094

7 0
2 years ago
What was anton van leeuwenhoek famous for
monitta

Answer:

He is known as the first microbiologist and also “the Father of Microbiology” because he was the first to observe bacteria underneath a microscope. He made many other significant discoveries in the field of biology and also made important changes to the microscope.

Explanation:

hope this helps. and if it did pls mark brainliest :)

3 0
3 years ago
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