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4 years ago

Propose a reasonable synthesis to get benzylamine from toluene

Chemistry

1 answer:

yawa3891 [41]4 years ago

4 0

Benzyl Amine is synthesized from Toluene in two steps;

Step 1: Bromination of Methyl Group in Toluene:
Bromination is carried out on methyl group present on Benzene ring through free radical mechanism by treating toluene with <span>N-Bromosuccinimide (NBS) and Benzyl Bromide is formed.

Step 2: Benzyl Bromide into Benzyl Amine;
This step is carried out utilizing a neme reaction "Gabriel Reaction". Benzyl bromide is treated with </span>Potassium Phthalamide and an intermediate is formed which on treatment with Hydrazine produces Benzyl amine.

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At equilibrium, the concentrations of reactants and products can be predicted using the equilibrium constant, Kc, which is a mat

mr Goodwill [35]

Answer:

The equillibrium constant Kc = 11.2233

Explanation:

Step 1:

aA + bB ⇔ cC + dD

with a, b, c and d = coefficients

Kc = equillibrium constant =( [C]^c [D]^d ) / ( [A]^a [B]^b)

Concentration at time t

[A] = 0.300 M

[B] =1.10 M

[C] = 0.450 M

Change :

A: -x

B: -2x

C: -x

The following reaction occurs and equillibrium is established

A + 2B ⇔ C

[A] = 0.110M

[B] = ?

[C] = 0.640 M

For A we see that after change: 0.3 -x = 0.11

Then for B we have 1.1 - 2x = ? ⇒ 1.1 -2 *0.19 = 0.72

This gives us for the equillibrium constant Kc = [C] / [A][B] ²

Kc = 0.64 / (0.11) * (0.72)² = 11.2233

8 0

3 years ago

The manufacture of steel is a very important process. complete this equation by balancing it. fe2o3 + c → fe + co2

DIA [1.3K]

The answer is $2Fe_2O_3 + 3C -> 3Fe + 3CO_2$

You must make sure each reactant has the same amount of subscripts on both sides of the equation.

7 0

4 years ago

Read 2 more answers

In the equation 2K+ 2H2O ---> 2KOH +H2

Law Incorporation [45]

The much hydrogen that is produced is 0.02 mol of H₂ (answer B)

Explanation

2K +2H₂O→ 2 KOH + H₂

Use the mole ratio to determine the moles of H₂

From equation above the K :H₂ is 2:1

Therefore the moles of H₂ = 0.04 x 1/2 = 0.02 mol of H₂

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3 years ago

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bogdanovich [222]

Answer:

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5 0

2 years ago

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Rank the following compounds from least acidic(rank 1) to most.A. AcetaldehydeB. Methyl acetate.C. N,N-dimethylacetamide1. least

Phoenix [80]

Answer:

N,N-dimethylacetamide < Methyl acetate < Acetaldehyde

Acetaldehyde - least acidic

Methyl acetate - acidic

N,N-dimethylacetamide - most acidic

Explanation:

The order of acidity of the organic compound under study is primarily influenced by their resonance effect. The resonance effect explains how polar a particular molecule is from the interaction between pi -bonds or a lone electron pair and a pi-bond in a molecule.

In acetaldehyde popularly known as ethanal, the CH₃CHO functional group -CHO is attached to an adjacent end of the compound, which has a lesser resonance effect than methyl acetate.

Methyl acetate, also known as methyl ethanoate, is an ester family with the formula CH₃COOCH₃ is also lesser in its acidity compared to N,N-dimethylacetamide.

Therefore, the order of acidity from the least acidic to the most is:

N,N-dimethylacetamide < Methyl acetate < Acetaldehyde

Acetaldehyde - least acidic

Methyl acetate - acidic

N,N-dimethylacetamide - most acidic

5 0

3 years ago