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exis [7]
3 years ago
6

What is the density of an object with a volume of 30ml and a mass of 90 grams

Chemistry
1 answer:
Crank3 years ago
8 0

Answer:

<h2>Density = 3 g/mL</h2>

Explanation:

Density of a substance can be found by using the formula

<h3>Density =   \frac{mass}{volume}</h3>

From the question

mass = 90 g

volume = 30 mL

Substitute the values into the above formula and solve for the Density

That's

<h3>Density  = \frac{90}{30}  \\  =  \frac{9}{3}</h3>

We have the final answer as

<h3>Density = 3 g/mL</h3>

Hope this helps you

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Naya [18.7K]
<h3>Answer:</h3>

A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.

<h3>Explanation:</h3>
  • A solution is made by dissolving a solute in a solvent.
  • For example dissolving a salt in a solvent such as water results to a solution.
  • Solution may either be saturated or unsaturated.
  • Unsaturated solution is a solution that can dissolve more solute upon addition because it has not reached saturation.
  • A saturated solution on the other hand is a solution that has maximum solute and the concentration of solute is maximum and thus the solvent can not dissolve any more solute.
  • Therefore, a saturated solutions contain maximum concentration of a solute dissolved in the solute.
8 0
3 years ago
The Germans were the first to send up a satellite into space.
vladimir2022 [97]

Answer: Thats false the Russians were the first

Explanation:

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3 years ago
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A solution was prepared by dissolving 2.2 g of an unknown solute in 16.7 g of CCl4. A thermal analysis was performed for this so
laila [671]

Answer:

Molar mass of unknown solute is 679 g/mol

Explanation:

Let us assume that the solute is a non-electrolyte.

For a solution with non-electrolyte solute remains dissolved in it -

Depression in freezing point of solution, \Delta T_{f}=K_{f}.m

where, m is molality of solute in solution and K_{f} is cryogenoscopic constant of solvent.

Here \Delta T_{f}=(-22.9^{0}\textrm{C})-(-28.7^{0}\textrm{C})=5.8^{0}\textrm{C}

If molar mass of unknown solute is M g/mol then-

                 m=\frac{\frac{2.2}{M}}{0.0167}mol/kg

So, 5.8^{0}\textrm{C}=29.9^{0}\textrm{C}/(mol/kg)\times \frac{\frac{2.2g}{M}}{0.0167}mol/kg

so, M = 679 g/mol

4 0
3 years ago
How many atoms are in 6.4 moles of vanadium
den301095 [7]
6.4 * 6.02 * 10^23 = 3.8528*10^24 atoms
Don't let the fact that it's vanadium throw you off, avagadros constant stays the same for all elements
3 0
3 years ago
Which of the following has to remain constant to allow you to use the combined gas law for calculations?
Mazyrski [523]

Answer:

Amount of gas

Explanation:

The combined gas law has to do with pressure, volume, and temperature. All of them can be a variable that you have to solve for. However, amount of gas is not a variable you can solve for, which means it must remain constant.

4 0
3 years ago
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