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exis [7]
3 years ago
6

What is the density of an object with a volume of 30ml and a mass of 90 grams

Chemistry
1 answer:
Crank3 years ago
8 0

Answer:

<h2>Density = 3 g/mL</h2>

Explanation:

Density of a substance can be found by using the formula

<h3>Density =   \frac{mass}{volume}</h3>

From the question

mass = 90 g

volume = 30 mL

Substitute the values into the above formula and solve for the Density

That's

<h3>Density  = \frac{90}{30}  \\  =  \frac{9}{3}</h3>

We have the final answer as

<h3>Density = 3 g/mL</h3>

Hope this helps you

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How many grams of MgCO3 are required to neutralize 200. mL of stomach acid HCl, which is equivalent to 0.0465 MHCl?
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<h3>Answer:</h3>

0.392 g

<h3>Explanation:</h3>

We are given the following;

Volume of HCl is 200 mL

Molarity of HCl is 0.0465M

We are required  to calculate the mass of MgCO₃ required

<h3>Step 1: Write the balanced equation for the reaction </h3>
  • The balanced equation for the reaction is;

MgCO₃(s) + 2HCl(aq) → MgCl₂(aq) + CO₂(g) + H₂O(l)

<h3>Step 2: Calculate the moles of HCl</h3>

When given the molarity of a compound and the volume, the number of moles can be calculated by;

Number of moles = Molarity × Volume

Therefore;

Volume of HCl = 0.0465 M × 0.2 L

                        = 0.0093 moles

<h3>Step 3: Calculating the number of moles of MgCO₃</h3>

From the equation, one mole of MgCO₃ reacts with two moles of HCl

Therefore, the mole ratio of MgCO₃ : HCl is 1 : 2

Hence, moles of MgCO₃ = Moles of HCl ÷ 2

                                         = 0.0093 moles ÷ 2

                                         = 0.00465 moles

<h3>Step 4: Mass of MgCO₃</h3>

To calculate the mass of a compound we need to multiply the molar mass of a compound with the number of moles.

Molar mass of MgCO₃ is 84.314 g/mol

Thus, Mass of MgCO₃ = 0.00465 moles × 84.314 g/mol

                                    = 0.392 g

Therefore, 0.392 g of MgCO₃ are required to neutralize the acid.

             

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6 0
3 years ago
Unheated
kumpel [21]

Explanation:

Using the Combined Gas Law, which is:

\frac{P_1V_1}{T_1}  =\frac{P_2V_2}{T_2}

<em>(With </em>P_1,V_1,T_1 <em>being initial pressure, volume and temperature; and</em>

<em />P_2,V_2,T_2<em> being the new values)</em>

<em />

We can move the units around in order to solve for P_2, which would look like this:

P_{2} =\frac{P_1V_1T_2}{V_2T_1}

Then we convert the Celsius temperature to Kelvin:

25 °C = 289 K

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And now, we plug in all of the values and solve, with volume remaining as a constant:

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1.25 atm <em>or </em>127 kPa

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